leetcode讲解–922. Sort Array By Parity II

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题目
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even.
Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even.
You may return any answer array that satisfies this condition.
Example 1:
Input: [4,2,5,7]
Output: [4,5,2,7]
Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.
Note:

2 <= A.length <= 20000
A.length % 2 == 0
0 <= A[i] <= 1000

题目地址
讲解
这道题需要新开一个等大的空间,还需要两个指针来分别记录偶数和奇数的位置。
Java 代码
class Solution {
public int[] sortArrayByParityII(int[] A) {
int[] result = new int[A.length];
int indexOfEven = 0;
int indexOfOdd = 1;
for(int i=0;i<A.length;i++){
if(A[i]%2==0){
result[indexOfEven] = A[i];
indexOfEven += 2;
}else{
result[indexOfOdd] = A[i];
indexOfOdd += 2;
}
}
return result;
}
}

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