leetcode讲解–728. Self Dividing Numbers

32次阅读

共计 827 个字符,预计需要花费 3 分钟才能阅读完成。

728. Self Dividing Numbers
A self-dividing number is a number that is divisible by every digit it contains.
For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.
Also, a self-dividing number is not allowed to contain the digit zero.
Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.
Example 1:
Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
Note:
The boundaries of each input argument are 1 <= left <= right <= 10000.
这道题需要注意几点:

不要直接对 i 进行操作,而是复制一份,对复制品进行操作
对 0 的过滤,0 不能做除数
while 的控制条件应该是 num!=0,而非 num/10!=0,否则会过滤掉个位数

Java 代码
class Solution {
public List<Integer> selfDividingNumbers(int left, int right) {
List<Integer> result = new ArrayList<>();
for(int i=left;i<=right;i++){
boolean flag = true;
int num=i;
while(num!=0){
int n = num%10;
if(n==0 || i%n!=0){
flag = false;
break;
}
num=num/10;
}
if(flag){
result.add(i);
}
}
return result;
}
}

正文完
 0