共计 1470 个字符,预计需要花费 4 分钟才能阅读完成。
结论是:
多线程下如果其中一个线程崩溃了会导致其他线程(整个进程)都崩溃;
多进程下如果其中一个进程崩溃了对其余进程没有影响;
多线程
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <pthread.h>
#include <assert.h>
void *fun1(void *arg)
{printf("fun1 enter\n");
while(1)
{printf("%s\n", __FUNCTION__);
usleep(1000 * 1000);
}
printf("fun1 exit\n");
return ((void *)1);
}
void *fun2(void *arg)
{printf("fun1 enter\n");
usleep(1000 * 3000);
char * ptr = (char *)malloc(sizeof(char));
printf("ptr1: 0x%x\n", ptr);
ptr = NULL;
printf("ptr2: 0x%x\n", ptr);
free(ptr);
memcpy(ptr, "123", 3);
printf("ptr3: 0x%x\n", ptr);
printf("fun2 exit\n");
return ((void *)2);
}
int main(void)
{
pthread_t tid1, tid2;
int err;
err = pthread_create(&tid1, NULL, fun1, NULL);
assert(0 == err);
err = pthread_create(&tid2, NULL, fun2, NULL);
assert(0 == err);
printf("main join ...\n");
// getchar();
pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
return 0;
}
多进程
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <pthread.h>
#include <assert.h>
void fun(void *arg)
{printf("fun1 enter\n");
usleep(1000 * 3000);
char * ptr = (char *)malloc(sizeof(char));
printf("ptr1: 0x%x\n", ptr);
ptr = NULL;
printf("ptr2: 0x%x\n", ptr);
free(ptr);
memcpy(ptr, "123", 3);
printf("ptr3: 0x%x\n", ptr);
printf("fun2 exit\n");
return ;
}
int main(int argc, char *argv[])
{assert(2 == argc);
pid_t pid;
int i;
for(i=0; i<atoi(argv[1]); i++)
{pid = fork();
if(0 > pid)
{printf("fork error");
exit(1);
}
else if(0 == pid)
{printf("child pid is %lu\n", (unsigned long)getpid());
fun(NULL);
exit(0);
}
}
printf("parent pid is %lu\n", (unsigned long)getpid());
while(-1 != wait(NULL)); // 等待所有子进程结束
printf("main return\n");
getchar();
return 0;
}
正文完