共计 2075 个字符,预计需要花费 6 分钟才能阅读完成。
归并排序(Java)
博客说明
文章所涉及的资料来自互联网整理和个人总结,意在于个人学习和经验汇总,如有什么地方侵权,请联系本人删除,谢谢!
归并排序介绍
归并排序(MERGE-SORT)是利用归并的思想实现的排序方法,该算法采用经典的分治(divide-and-conquer)策略(分治法将问题分 (divide) 成一些小的问题然后递归求解,而治 (conquer) 的阶段则将分的阶段得到的各答案 ” 修补 ” 在一起,即分而治之)。
代码
package cn.guizimo.sort;
import java.util.Arrays;
public class MergetSort {public static void main(String[] args) {int arr[] = {8, 4, 5, 7, 1, 3, 6, 2};
int temp[] = new int[arr.length];
System.out.println("排序前");
System.out.println(Arrays.toString(arr));
mergeSort(arr, 0, arr.length - 1, temp);
System.out.println("排序后");
System.out.println(Arrays.toString(arr));
}
public static void mergeSort(int[] arr, int left, int right, int[] temp) {if (left < right) {int mid = (left + right) / 2;
mergeSort(arr, left, mid, temp);
mergeSort(arr, mid + 1, right, temp);
merge(arr, left, mid, right, temp);
}
}
public static void merge(int[] arr, int left, int mid, int right, int[] temp) {
int i = left;
int j = mid + 1;
int t = 0;
while (i <= mid && j <= right) {if (arr[i] <= arr[j]) {temp[t] = arr[i];
t += 1;
i += 1;
} else {temp[t] = arr[j];
t += 1;
j += 1;
}
}
while (i <= mid) {temp[t] = arr[i];
t += 1;
i += 1;
}
while (j <= right) {temp[t] = arr[j];
t += 1;
j += 1;
}
t = 0;
int tempIndex = left;
while (tempIndex <= right) {arr[tempIndex] = temp[t];
t += 1;
tempIndex += 1;
}
}
}
测试
速度测试
package cn.guizimo.sort;
import java.util.Arrays;
public class MergetSort {public static void main(String[] args) {
int max = 80000;
int[] arr = new int[max];
for (int i = 0; i < max; i++) {arr[i] = (int)(Math.random() * 8000000);
}
int temp[] = new int[arr.length];
long date1 = System.currentTimeMillis();
mergeSort(arr, 0, arr.length - 1, temp);
long date2 = System.currentTimeMillis();
System.out.println("归并排序"+max+"数组的时间为:"+(date2-date1));
}
public static void mergeSort(int[] arr, int left, int right, int[] temp) {if (left < right) {int mid = (left + right) / 2;
mergeSort(arr, left, mid, temp);
mergeSort(arr, mid + 1, right, temp);
merge(arr, left, mid, right, temp);
}
}
public static void merge(int[] arr, int left, int mid, int right, int[] temp) {
int i = left;
int j = mid + 1;
int t = 0;
while (i <= mid && j <= right) {if (arr[i] <= arr[j]) {temp[t] = arr[i];
t += 1;
i += 1;
} else {temp[t] = arr[j];
t += 1;
j += 1;
}
}
while (i <= mid) {temp[t] = arr[i];
t += 1;
i += 1;
}
while (j <= right) {temp[t] = arr[j];
t += 1;
j += 1;
}
t = 0;
int tempIndex = left;
while (tempIndex <= right) {arr[tempIndex] = temp[t];
t += 1;
tempIndex += 1;
}
}
}
感谢
尚硅谷
万能的网络
以及勤劳的自己
正文完