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1.mysql 中实现 json 字段查问
select * from item where is_remove = 0 and json_extract(item_info,'$.GoodType') ='cat'
2.JPA @Query 实现 mysql 中 json 字段查问
@Query(value = "select * from item where json_extract(item_info,?1) =?2 and item_id in (?3)",nativeQuery = true)
List<Item> selectItems(String featuresKey,String featuresValue,List<Long> itemIds);
List<Item> items = itemRepository.selectItemListByFeatures("$.GoodType","cat",ids);
3.Specification 实现 mysql 中 json 字段查问
items=itemRepository.findAll(new Specification<Item>() {
@Override
public Predicate toPredicate(Root<Item> root, CriteriaQuery<?> query, CriteriaBuilder cb) {List<Predicate> list = new ArrayList<>();
for(Features fea:features){if( fea.getFeaturesAliasName()!=null && fea.getFeaturesValue()!= null){
list.add(cb.equal(
cb.function(
"JSON_EXTRACT",
String.class,
root.get("itemInfo"),
cb.literal("$."+fea.getFeaturesAliasName())
), fea.getFeaturesValue())
);
}
}
list.add(cb.in(root.get("itemId")).value(itemIds));
Predicate[] p = new Predicate[list.size()];
query.where(cb.and(list.toArray(p)));
return query.getGroupRestriction();}
});
4. 备注类
Item{
"itemId":"1",
"itemInfo":{"GoodId":"1002","GoodType":"cat","GoodName":"catyeall"}
}
Features{
"featuresName":"GoodType",
"featuresValue":"cat"
}
5. 附录
深入浅出学 Spring Data JPA
Spring Data JPA 与 PostgreSQL 的 jsonb 类型集成与反对
正文完
发表至: spring-data-jpa
2021-01-26