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对于 es 的数据类型来说,如果它是一个简单类型,而咱们须要把简单类型进行检索,那么应该定义成 nested
类型,而对于它的检索,如果是非汇合数据,它与其它类型没有别离;而如果你的 nested 存储的数据是一个汇合,那在进行不等于这种操作时,就须要阐明一下了。
举例子
"id": "1",
"operate": [
{
"actionTime": "2017-03-21 11:57:37.700",
"operateType": "WangLu",
"wordNum": "3188",
"userName": "zidongluru"
},
{
"actionTime": "2017-03-21 11:57:37.700",
"operateType": "DaoRu",
"wordNum": "3188",
"userName": "qinbixue1609"
}
]
对于下面的数据,其中 operate 是一个 nested 类型的,它存储数据为一个汇合,咱们查问 operateType 不等于 WangLu 的数据,如果间接应用 not_must 配合 term,那后果是不对的,它会把这个文档失常返回,为什么?按说这个 operate 里是蕴含了 WangLu
的,如果蕴含它是不应该返回的;这就是 es 检索 nested 汇合解决不等于的问题,当会查问所有汇合中的元素,有一个不等于 WangLu
的,它就认为是不等于的,这与咱们的需要不合乎,所以要想其它办法。
script 脚本检索 nested 汇合失败
{
"size": 5,
"_source": [
"Gid",
"Type",
"operate"
],
"query": {
"bool": {
"must": [
{
"nested": {
"path": "operate",
"query": {
"script": {"script": "doc['operate.operateType'].stream().map(o->o).filter(o->o=='YiJiaoSu').count()==0"}
}
}
},
{
"term": {"Gid": "1970325267114815"}
}
]
}
}
}
应用 function 形式解决了这个问题
-
参考
https://cloud.tencent.com/developer/article/1973186
https://cloud.tencent.com/developer/article/1973186
https://stackoverflow.com/questions/54022283/elasticsearch-search-query-why-params-source-nested-field-size-is-not-workin
{ "size": 5, "_source": [ "Gid", "Type", "operate" ], "query": { "bool": { "must": [ { "function_score": { "query": {"match_all": {} }, "functions": [ { "script_score": { "script": {"source": "params._source.operate.stream().map(o->o.operateType).filter(o->o=='YiJiaoSu').count()==0 ? 1 : 0"} } } ], "min_score": 1 } }, { "term": {"Id": "1970325267114815"} } ] } } }
这种因为是汇合里的汇合再检索,所以须要和其它检索条件一起用,全表检索,性能比拟差。
翻译成 java 客户端代码
String val = "条件";
String name = "nested 外部字段名";
String scoreStr = "params._source.operate==null || params._source.operate.stream().map(o->o." + name + ").filter(o->o=='" + val + "').count()==0? 1 : 0";
Script sc = new Script(ScriptType.INLINE, Script.DEFAULT_SCRIPT_LANG, scoreStr, MapUtil.empty());
ScriptScoreFunctionBuilder builder = new ScriptScoreFunctionBuilder(sc);
FunctionScoreQueryBuilder scoreBuilder = QueryBuilders.functionScoreQuery(builder);
scoreBuilder.setMinScore(1);
scoreBuilder.scoreMode(FunctionScoreQuery.ScoreMode.FIRST);
queryIncludeBuilder.must(scoreBuilder);
正文完