共计 5112 个字符,预计需要花费 13 分钟才能阅读完成。
以下例子皆以该数组为根底
var arr = [
1, 1, 15, 15,
'true', 'false',true,
false, 'false', true, 0,
undefined, null, null,
NaN, 'NaN', NaN, 'NaN', false, undefined,
0, 'a', 'a', 'true',
{'name': 'jack', 'age': 18},
{'age': 18, 'name': 'jack'},
{'name': 'lucy', 'age': 20},
{'name': 'lucy', 'age': 22}
];
1. Set
毛病:对象无奈去重
function unique (arr) {return Array.from(new Set(arr))
}
console.log(unique(arr)) // length:16
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN","a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
或者
[...new Set(arr)] // 后果跟下面统一
2. Map
毛病:对象无奈去重
function unique(arr) {let map = new Map();
let array = new Array(); // 数组用于返回后果
for (let i = 0; i < arr.length; i++) {if(map.has(arr[i])) { // 如果有该 key 值
map.set(arr[i], true);
} else {map.set(arr[i], false); // 如果没有该 key 值
array .push(arr[i]);
}
}
return array ;
}
console.log(unique(arr)) // length: 16
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN","a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
3. for + splice
毛病:对象无奈去重,NaN
无奈去重
function unique(arr){for(var i = 0; i < arr.length; i++){for(var j = i + 1; j < arr.length; j++){if(arr[i] === arr[j]){arr.splice(j,1);
j--;
}
}
}
return arr;
}
console.log(unique(arr)) // length: 17
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN",NaN, "a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
4. for + indexOf
毛病:对象无奈去重,NaN
无奈去重
function unique(arr) {if (!Array.isArray(arr)) {console.log('type error!')
return
}
var array = [];
for (var i = 0; i < arr.length; i++) {if (array .indexOf(arr[i]) === -1) {array .push(arr[i])
}
}
return array;
}
console.log(unique(arr)) // length: 17
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN",NaN, "a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
5. for + includes
毛病:对象无奈去重
function unique(arr) {if (!Array.isArray(arr)) {console.log('type error!')
return
}
var array =[];
for(var i = 0; i < arr.length; i++) {if( !array.includes( arr[i]) ) {array.push(arr[i]);
}
}
return array
}
console.log(unique(arr)) // length: 16
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN","a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
6. for + sort
毛病:对数字 / 字母排序无效,否则须要传入特定条件进行排序
function unique(arr) {if (!Array.isArray(arr)) {console.log('type error!')
return;
}
// todo 应该传入条件排序
arr = arr.sort()
var arrry= [arr[0]];
for (var i = 1; i < arr.length; i++) {if (arr[i] !== arr[i-1]) {arrry.push(arr[i]);
}
}
return arrry;
}
console.log(unique(arr)) // length: 21
7. filter + hasOwnProperty
毛病:将 object 类型都去掉了,仅剩一个
function unique(arr) {var obj = {};
return arr.filter(function(item, index, arr){console.log('typeof item + item', typeof item + item,'>>>>', obj.hasOwnProperty(typeof item + item))
return obj.hasOwnProperty(typeof item + item) ? false : (obj[typeof item + item] = true)
})
}
console.log(unique(arr)) // length: 13
8. filter + indexOf
毛病:对象无奈去重,不能辨认 NaN
和”NaN“
function unique(arr) {return arr.filter(function(item, index, arr) {
// 以后元素,在原始数组中的第一个索引 == 以后索引值,否则返回以后元素
return arr.indexOf(item, 0) === index;
});
}
console.log(unique(arr)) // length: 15
// [1,15,"true","false",true,false,0,undefined,null,"NaN","a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
9. reduce + includes
毛病:对象无奈去重
function unique(arr){return arr.reduce((prev,cur) => prev.includes(cur) ? prev : [...prev,cur],[]);
}
console.log(unique(arr)); // length: 16
// [1,15,"true","false",true,false,0,undefined,null,NaN,"NaN","a",{"name":"jack","age":18},{"age":18,"name":"jack"},{"name":"lucy","age":20},{"name":"lucy","age":22}]
10. lodash 工具库
后果:完满去重
Lodash: 一个一致性、模块化、高性能的 JavaScript 实用工具库
var oScript = document.createElement('script');
oScript.type = 'text/javascript';
oScript.async = true;
oScript.src="https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js";
document.body.append(oScript)
_.uniqWith(arr, _.isEqual); // length: 15
11. 比照
办法 | 长处 | 毛病 |
---|---|---|
Set | 代码量少 | 对象无奈去重 |
Map | 对象无奈去重 | |
for + splice | 对象无奈去重,NaN 无奈去重 | |
for + indexOf | 对象无奈去重,NaN 无奈去重 | |
for + includes | 对象无奈去重 | |
for + sort | 对数字 / 字母类较无效 | 需传入特定条件进行排序 |
filter + hasOwnProperty | 将 object 类型都去掉了,仅剩一个 | |
filter + indexOf | 对象无奈去重,不能辨认 NaN 和”NaN“ | |
reduce + includes | 对象无奈去重 | |
lodash.js | 工具库,使用方便,完满去重 |
总结
以上的办法能够自由组合,除了对象的去重须要非凡解决外,其余的根本都实用。如果数组中掺杂了对象,那么咱们只须要判断对象类型,针对对象做非凡的去重解决即可。
数组对象去重
以下例子皆以这个数组为前提:
var arr = [{'id': 1, 'name': 'jack', 'age': 18},
{'id': 1, 'age': 18, 'name': 'jack'},
{'id': 2, 'name': 'lucy', 'age': 20},
{'id': 3, 'name': 'lucy', 'age': 22},
{'id': 3, 'name': 'lucy', 'age': 22},
{'id': 4, 'name': 'lucy', 'age': 22}
]
1. reduce
function unique(arr){let obj = {}
return arr.reduce((prev,cur) => {obj[cur.id] ? "" : obj[cur.id] = true && prev.push(cur);
return prev
},[]); // 设置 prev 默认类型为数组,并且初始值为空的数组
}
console.log(unique(arr));
2. Map
function unique(arr){let map = new Map();
for (let item of arr) {if (!map.has(item.id)) {map.set(item.id, item);
}
}
return [...map.values()];
}
console.log(unique(arr));
3. Map + Object.values()
function unique(arr){let obj = {}
arr.map(item => {obj[item.id] = item
})
console.log(obj)
return Object.values(obj)
}
console.log(unique(arr));
4. 双重循环
var temp = []
function unique(arr){arr.forEach(function(a) {var check = temp.every(function(b) {return a.id !== b.id;})
check ? temp.push(a) : ''
})
return temp;
}
console.log(unique(arr));
5. 冒泡排序法
function unique(arr){for (var i = 0; i < arr.length - 1; i++) {for (var j = i + 1; j < arr.length; j++) {if (arr[i].id == arr[j].id) {arr.splice(j, 1);
j--;
}
}
}
return arr;
}
console.log(unique(arr));
正文完