共计 3261 个字符,预计需要花费 9 分钟才能阅读完成。
有一个群友在群里问个如何疾速搭建一个搜索引擎,在搜寻之后我看到了这个
代码所在
- Git:https://github.com/asciimoo/s…
官网很贴心,很不便的是曾经提供了 docker 镜像,根本 pull 下来就能够很不便的应用了,执行命令
cid=$(sudo docker ps -a | grep searx | awk '{print $1}')
echo searx cid is $cid
if ["$cid" != ""];then
sudo docker stop $cid
sudo docker rm $cid
fi
sudo docker run -d --name searx -e IMAGE_PROXY=True -e BASE_URL=http://yourdomain.com -p 7777:8888 wonderfall/searx
而后就能够应用了, 失常查看 docker 的状态,就能够失常的应用了
思考
怎么样,是不是很不便,咱们先看看源码是怎么样实现的
咱们关上外面的代码,其实实质就是将 request 之后的后果做一个大的聚合,至于数据起源,咱们能够是来于 DB, 或者文件,咱们能够看一下他的外围代码
from urllib import urlencode
from json import loads
from collections import Iterable
search_url = None
url_query = None
content_query = None
title_query = None
suggestion_query = ''results_query =''
# parameters for engines with paging support
#
# number of results on each page
# (only needed if the site requires not a page number, but an offset)
page_size = 1
# number of the first page (usually 0 or 1)
first_page_num = 1
def iterate(iterable):
if type(iterable) == dict:
it = iterable.iteritems()
else:
it = enumerate(iterable)
for index, value in it:
yield str(index), value
def is_iterable(obj):
if type(obj) == str:
return False
if type(obj) == unicode:
return False
return isinstance(obj, Iterable)
def parse(query):
q = []
for part in query.split('/'):
if part == '':
continue
else:
q.append(part)
return q
def do_query(data, q):
ret = []
if not q:
return ret
qkey = q[0]
for key, value in iterate(data):
if len(q) == 1:
if key == qkey:
ret.append(value)
elif is_iterable(value):
ret.extend(do_query(value, q))
else:
if not is_iterable(value):
continue
if key == qkey:
ret.extend(do_query(value, q[1:]))
else:
ret.extend(do_query(value, q))
return ret
def query(data, query_string):
q = parse(query_string)
return do_query(data, q)
def request(query, params):
query = urlencode({'q': query})[2:]
fp = {'query': query}
if paging and search_url.find('{pageno}') >= 0:
fp['pageno'] = (params['pageno'] - 1) * page_size + first_page_num
params['url'] = search_url.format(**fp)
params['query'] = query
return params
def response(resp):
results = []
json = loads(resp.text)
if results_query:
for result in query(json, results_query)[0]:
url = query(result, url_query)[0]
title = query(result, title_query)[0]
content = query(result, content_query)[0]
results.append({'url': url, 'title': title, 'content': content})
else:
for url, title, content in zip(query(json, url_query),
query(json, title_query),
query(json, content_query)
):
results.append({'url': url, 'title': title, 'content': content})
if not suggestion_query:
return results
for suggestion in query(json, suggestion_query):
results.append({'suggestion': suggestion})
return results
后果
每个 response 的时候咱们都要以轻松的定制返回的数据(能够是网络,能够是数据库,能够是文件),那咱们进一步想一下,如果咱们能够 hack response 后果,那咱们齐全能够将本人爬来的数据做为返回后果。如果是 1024 之类的,齐全能够打造本人的“喜好”小引擎,代码我就不贴了,大家能够本人入手本人玩玩。联合 jieba 分词,能够更好玩一点。
正文完