1.多表父子级关系利用流来解决
private List<AddressInfo> children;
List<AddressInfo> collect1 = addressInfo.stream().map(m1 -> {
List<AddressInfo> collect = addressInfo.stream().filter(
m2 -> Objects.equals(m1.getId(), m2.getPId())).collect(Collectors.toList());
m1.setChildren(collect);
return m1;
}).collect(Collectors.toList());
阐明:m1 父级信息 m2 子级信息
2单表父子级关系解决
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
/**
* 3.循环解决全副数据,转为父子级对象
*/
for (AddressInfo vo : addressInfo) {
Map<String, Object> map = new HashMap<String, Object>(8);
if (vo.getPId() == 0) {
map.put("children", getChildren(addressInfo, vo.getId()));
map.put("pId", vo.getPId());
寄存子级数据
list.add(map);
}
}
PageInfo<AddressInfo> pageInfo = new PageInfo<>(addressInfo);
return success(list, pageInfo.getTotal());
}
public List<Map<String, Object>> getChildren(List<AddressInfo> data, Integer wzflid) {
/**
* 1.对数据校验解决
*/
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
if (data == null || data.size() == 0 || wzflid == null) {
return list;
}
/**
* 2.遍历匹配父子级关系数据
*/
for (AddressInfo vo : data) {
Map<String, Object> map = new HashMap<String, Object>(8);
if (wzflid.equals(vo.getPId())) {
map.put("pId", vo.getPId());
list.add(map);
}
}
return list;
}
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