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leetcode:
https://leetcode.cn/problems/implement-queue-using-stacks/des…
解题思路:
type MyQueue struct {stack []int
back []int}
/** Initialize your data structure here. */
func Constructor() MyQueue {
return MyQueue{stack: make([]int, 0),
back: make([]int, 0),
}
}
/** Push element x to the back of queue. */
func (this *MyQueue) Push(x int) {for len(this.back) != 0 {val := this.back[len(this.back)-1]
this.back = this.back[:len(this.back)-1]
this.stack = append(this.stack, val)
}
this.stack = append(this.stack, x)
}
/** Removes the element from in front of queue and returns that element. */
func (this *MyQueue) Pop() int {for len(this.stack) != 0 {val := this.stack[len(this.stack)-1]
this.stack = this.stack[:len(this.stack)-1]
this.back = append(this.back, val)
}
if len(this.back) == 0 {return 0}
val := this.back[len(this.back)-1]
this.back = this.back[:len(this.back)-1]
return val
}
/** Get the front element. */
func (this *MyQueue) Peek() int {for len(this.stack) != 0 {val := this.stack[len(this.stack)-1]
this.stack = this.stack[:len(this.stack)-1]
this.back = append(this.back, val)
}
if len(this.back) == 0 {return 0}
val := this.back[len(this.back)-1]
return val
}
/** Returns whether the queue is empty. */
func (this *MyQueue) Empty() bool {return len(this.stack) == 0 && len(this.back) == 0
}
正文完