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扩大 Elasticsearch 客户端简化 ES 查问(.net core/framework)
Elasticsearch .net 客户端提供了两种形式进行查问操作
基于对象结构查问
new IdsQuery
{
Name = "named_query",
Boost = 1.1,
Values = new List<Id> {1, 2, 3, 4},
}
基于 lambda 语法查问
q
.Ids(c => c
.Name("named_query")
.Boost(1.1)
.Values(1, 2, 3, 4)
)
两种形式各有优缺点,最次要起因是条件稍有点简单后,感觉像在套娃,一层套一层,特地是 lambda
如:
var searchResults = this.Client.Search<Project>(s => s
.Query(q => q
.Bool(b => b
.Should(bs => bs.Term(p => p.Name, "x"),
bs => bs.Term(p => p.Name, "y")
)
)
)
);
官网文档有简化的写法,Writing bool queries | Elasticsearch.Net and NEST: the .NET clients [7.x] | Elastic
然而这种办法式的调用还是很麻烦,防止不了办法组合
对于个别逻辑查问,通过运算符 (d,!=,>,<) 解决会更简洁
以下示例 ES 版本为 7.x
- 装置 nuget 包:CRL.Elasticsearch
- using CRL;
using CRL.Elasticsearch;
定义数据源
var builder = DBConfigRegister.GetInstance();
builder.UseElasticsearch();
builder.RegisterDBAccessBuild(dbLocation =>
{var dBAccessBuild= new DBAccessBuild(DBType.ES, "http://127.0.0.1:9200/testIndex");
// 定义连贯设置
Func<ConnectionSettings, ConnectionSettings> func = (setting) =>
{setting.DefaultMappingFor<GoodsInfo>(m => m.IndexName("testIndex"));
setting.DefaultMappingFor<GoodsInfoChild>(m => m.IndexName("testIndex"));
return setting;
};
dBAccessBuild.Data = func;
return dBAccessBuild;
});
定义查问对象
public class GoodsService:BaseProvider<GoodsInfo>
{}
初始数据
public static void CreateMapping()
{var service = new GoodsService();
service.DropTable();
service.CreateEsIndex();
var list = new List<GoodsInfo>();
for (int i = 1; i < 11; i++)
{list.Add(new GoodsInfo { Id = i.ToString(), DataType = "Goods", Name = "goods" + i, Number = i });
}
service.BatchInsert(list);
var service2 = new GoodsInfoChildService();
var childs = new List<GoodsInfoChild>();
childs.Add(new GoodsInfoChild("1", "100", "History") {GroupCode = "001"});
childs.Add(new GoodsInfoChild("1", "200", "History") {GroupCode = "001"});
service2.BatchInsert(childs);
}
按逻辑查问
var service = new GoodsService();
var list = service.QueryList(b => b.DataType == "Goods" && b.Id != "2");
Console.WriteLine($"count should 9 {list.Count == 9}");
对后果进行分组
public static void testAggregationCount()
{var service = new GoodsService();
var query = service.GetLambdaQuery();
query.Where(b => b.DataType == "Goods");
query.GroupBy(b => new { b.DataType, b.Name});
var list = query.ToAggregationCount();
Console.WriteLine($"count should 2 {list.Count == 2}");
}
指定查询方法
public static void testMethodAll()
{var service = new GoodsService();
var query = service.GetLambdaQuery();
var ids = new List<Id>();
ids.Add("1");
query.Where(b => b.WithIdsQuery(ids));
query.Where(b => b.Name.WithWildcardQuery("goods*"));
query.Where(b => b.Name.WithTermQuery("goods"));
query.Where(b => b.Name.WithMatchQuery("goods", Operator.And));
query.Where(b => b.Name.WithMatchPhraseQuery("goods"));
query.Where(b => b.WithMultiMatchQuery(new string[] {"Name", "DataType"}, "goods", Operator.And, TextQueryType.BestFields));
query.Where(b => b.WithQueryBase(new WildcardQuery
{
Field = "Name",
Value = "goods"
}));
}
子查问判断
public static void testChildQuery()
{var service = new GoodsService();
var query = service.GetLambdaQuery().Where(b => b.DataType == "Goods");
var queryChild = query.CreateQuery<GoodsInfoChild>();
queryChild.Where(b => b.GroupCode == "001");
query.HasChild(queryChild);
var list = query.ToList();
Console.WriteLine($"count should 1 {list.Count == 1}");
}
源码示例参考
Data/esTest · hubroxxl/CRL – 码云 – 开源中国 (gitee.com)
正文完
发表至: elasticsearch
2021-07-07