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客户端 / 服务端 编程模式
- 服务端长期保留于网络(公开本人的 IP 地址),并期待客户端连贯
- 客户端发动连贯动作,并期待服务端回应
-
特点:
- 服务端无奈被动连贯客户端
- 客户端只能依照预约义的形式(协定)连贯服务端
服务端编程模式
1. 筹备网络连接
2. 绑定端口
3. 进入端口监听状态
4. 期待连贯
服务端外围工作:绑定 & 监听 & 接管
- 绑定:
int bind(int sock, struct sockaddr *addr, socklen_t addrlen);
- 监听:
int listen(int sock, int backlog);
- 接管:
int accept(int sock, struct sockaddr *addr, socklen_t addrlen);
深度分析服务端
- 服务端 socket 只用于接管连贯,不进行理论通信
- 当接管到连贯时,accept() 函数返回与客户端通信的 socket
- 服务端 socket 产生用于通信的客户端 socket
所以,socket 到底是什么玩意?如何了解?
深刻了解 socket() 函数
-
socket() 是什么?
- socket() 是一个多功能函数
-
socket() 返回的又是什么?
- socket() 的返回值是用于通信的资源标识符
-
socket() 还能做什么?
- socket() 可提供不同类型的通信性能(本地过程间通信)
编程试验:服务端编程初体验
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <stdio.h>
#include <unistd.h>
#include <string.h>
int main()
{
int server = 0;
struct sockaddr_in saddr = {0};
int clinet = 0;
struct sockaddr_in caddr = {0};
socklen_t asize = 0;
int len = 0;
char buf[32] = {0};
int r = 0;
server = socket(PF_INET, SOCK_STREAM, 0);
if (server == -1) {printf("server socket error\n");
return -1;
}
saddr.sin_family = AF_INET;
saddr.sin_addr.s_addr = htonl(INADDR_ANY);
saddr.sin_port = htons(8899);
if (bind(server, (struct sockaddr*)&saddr, sizeof(saddr)) == -1) {printf("server bind error\n");
return -1;
}
if (listen(server, 1) == -1) {printf("server listen error\n");
return -1;
}
printf("server start success\n");
asize = sizeof(caddr);
clinet = accept(server, (struct sockaddr*)&caddr, &asize);
if (clinet == -1) {printf("client accept error\n");
return -1;
}
printf("client: %d\n", clinet);
len = 0;
do {
int i = 0;
r = recv(clinet, buf, sizeof(buf), 0);
if (r > 0) {len += r;}
for (i=0; i<r; ++i) {printf("%c", buf[i]);
}
} while (len < 64);
printf("\n");
send(clinet, "hello word!", 12, 0);
sleep(1);
close(clinet);
close(server);
return 0;
}
INADDR_ANY => "0.0.0.0"
, 示意本机的连贯全副承受(如,本机有多个网卡进而有多个 IP 时)
客户端 / 服务端 编程的外围模式
- 服务端长时间运行(死循环)接管客户端的申请
- 客户端连贯后向服务端发送申请(协定数据)
服务端外围编程模式
编程试验:客户端 / 服务端编程试验
- 服务端继续监听客户端连贯
- 服务端被连贯后 echo 客户端数据
- 服务端接管到 quit 后断开连接
- 客户端接管用户输出并发送到服务端
服务端
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <stdio.h>
#include <unistd.h>
#include <string.h>
int main()
{
int server = 0;
struct sockaddr_in saddr = {0};
int client = 0;
struct sockaddr_in caddr = {0};
socklen_t asize = 0;
int len = 0;
char buf[32] = {0};
int r = 0;
server = socket(PF_INET, SOCK_STREAM, 0);
if (server == -1) {printf("server socket error\n");
return -1;
}
saddr.sin_family = AF_INET;
saddr.sin_addr.s_addr = htonl(INADDR_ANY);
saddr.sin_port = htons(8888);
if (bind(server, (struct sockaddr*)&saddr, sizeof(saddr)) == -1) {printf("server bind error\n");
return -1;
}
if (listen(server, 1) == -1) {printf("server listen error\n");
return -1;
}
printf("server start success\n");
while (1) {asize = sizeof(caddr);
client = accept(server, (struct sockaddr*)&caddr, &asize);
if (client == -1) {printf("client accept error\n");
return -1;
}
printf("client: %d\n", client);
do {r = recv(client, buf, sizeof(buf), 0);
if (r > 0) {printf("Receive: %s\n", buf);
if (strcmp(buf, "quit") != 0) {len = send(client, buf, r, 0);
}
else {break;}
}
} while (r > 0);
close(client);
}
close(server);
return 0;
}
客户端
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <stdio.h>
#include <unistd.h>
#include <string.h>
int main()
{
int sock = 0;
struct sockaddr_in addr = {0};
int len = 0;
char buf[128] = {0};
char input[32] = {0};
int r = 0;
sock = socket(PF_INET, SOCK_STREAM, 0);
if (sock == -1) {printf("socket error\n");
return -1;
}
addr.sin_family = AF_INET;
addr.sin_addr.s_addr = inet_addr("192.168.2.46");
addr.sin_port = htons(8888);
if (connect(sock, (struct sockaddr*)&addr, sizeof(addr)) == -1) {printf("connect error\n");
return -1;
}
printf("connect success\n");
while (1) {printf("Input:");
scanf("%s", input);
len = send(sock, input, strlen(input) + 1, 0);
r = recv(sock, buf, sizeof(buf), 0);
if (r > 0) {printf("Receive: %s\n", buf);
}
else {break;}
}
close(sock);
return 0;
}
思考:如何加强服务端能力,同时反对多个客户端?
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