共计 3826 个字符，预计需要花费 10 分钟才能阅读完成。
加号运算符重载
对于内置数据类型，编译器晓得如何运算
然而对于本人封装的类，编译器无奈进行运算
这时能够通过本人定义运算符重载进行运算
operator
通过成员函数重载 + 号
#include<iostream>
using namespace std;
class Person
{
public:
int m_a;
int m_b;
// 通过成员函数实现重载
Person operator+ (Person &p)
{
// 创立一个长期变量
Person temp;
temp.m_a = this->m_a + p.m_a;
temp.m_b = this->m_b + p.m_b;
return temp;
}
};
void test01()
{
Person p1;
p1.m_a = 66;
p1.m_b = 44;
Person p2;
p2.m_a = 6;
p2.m_b = 4;
Person p3;
// 通过函数原型调用
p3 = p1.operator+(p2);
// 简便调用
//p3 = p1 + p2;
cout << "p3.m_a:" << p3.m_a << endl;
cout << "p3.m_b:" << p3.m_b << endl;
}
int main()
{test01();
system("pause");
return 0;
}留神两种调用形式
通过函数原型调用
**p3 = p1.operator+(p2);**简便调用
**p3 = p1 + p2;**
通过全局函数重载 + 号
#include<iostream>
using namespace std;
class Person
{
public:
int m_a;
int m_b;
};
// 通过全局函数实现重载
Person operator+ (Person& p1, Person& p2)
{
// 创立一个长期变量
Person temp;
temp.m_a = p1.m_a + p2.m_a;
temp.m_b = p1.m_b + p2.m_b;
return temp;
}
void test01()
{
Person p1;
p1.m_a = 66;
p1.m_b = 44;
Person p2;
p2.m_a = 6;
p2.m_b = 4;
Person p3;
// 函数原型调用
p3 = operator+(p1,p2);
// 简便调用
//p3 = p1 + p2;
cout << "p3.m_a:" << p3.m_a << endl;
cout << "p3.m_b:" << p3.m_b << endl;
}
int main()
{test01();
system("pause");
return 0;
}留神两种调用形式
通过函数原型调用
**p3 = operator+(p1,p2);**简便调用
**p3 = p1 + p2;**
运算符重载产生函数重载
运算符重载能够产生函数重载：Person+int 等等
#include<iostream>
using namespace std;
class Person
{
public:
int m_a;
int m_b;
};
// 通过全局函数实现重载
Person operator+ (Person& p1, int num)
{
// 创立一个长期变量
Person temp;
temp.m_a = p1.m_a + num;
temp.m_b = p1.m_b + num;
return temp;
}
void test01()
{
Person p1;
p1.m_a = 66;
p1.m_b = 44;
Person p2;
p2.m_a = 6;
p2.m_b = 4;
Person p3;
// 函数原型调用
//p3 = operator+(p1,55);
// 简便调用
p3 = p1 + 55;
cout << "p3.m_a:" << p3.m_a << endl;
cout << "p3.m_b:" << p3.m_b << endl;
}
int main()
{test01();
system("pause");
return 0;
}调用办法和定义方法与下面雷同，不再多余赘述
总结
1、零碎内置数据类型的表达式不可扭转
2、不要滥用运算符重载
左移运算符
不利用成员函数重载左移运算符
没有具体演示，因为报错，我也没写进去
上面通过全局函数实现
#include<iostream>
using namespace std;
class Person
{
public:
int m_a;
int m_b;
};
ostream& operator<<(ostream& cout,Person&p)
{
cout << "p.m_a=" <<p. m_a << "p.m_b=" <<p. m_b << endl;
return cout;
}
void test01()
{
Person p1;
p1.m_a = 44;
p1.m_b = 66;
cout << p1 << endl;
}
int main()
{test01();
system("pause");
return 0;
}因为要实现链式，实现追加，所以返回值必须是 ostream
总结
配合友元实现自定义输入类型
递增运算符重载
递增运算符重载
#include<iostream>
using namespace std;
class myInt
{friend ostream& operator<<(ostream& cout, myInt num);
public:
myInt()
{this->m_a = 0;}
// 前置 ++ 运算符重载
myInt& operator++()// 返回援用是为了始终对一个数据进行递增，否则函数默认返回一个新的数
{
// 先进行 ++
m_a++;
// 而后返回本身
return *this;
}
// 后置 ++ 运算符重载
myInt operator++(int)//int 示意占位参数，用于辨别前置后置参数
{
// 先记录以后的值
myInt temp=*this;
// 再递增
m_a++;
// 而后返回记录的值
return temp;
}
private:
int m_a;
};
// 左移运算符重载
ostream& operator<<(ostream& cout, myInt num)
{
cout << num.m_a;
return cout;
}
void test01()
{
myInt myint;
cout << myint << endl;
cout << ++myint << endl;
cout << myint << endl;
}
int main()
{test01();
system("pause");
return 0;
}赋值运算符重载
#include<iostream>
using namespace std;
class Person
{
public:
Person(int num)// 将数据开拓到堆区
{m_a = new int(num);
}
~Person()
{if (m_a != NULL)
{
delete m_a;
m_a = NULL;
}
}
// 重载赋值运算符
Person& operator=(Person &p)// 返回值用 Person 返回自身，可执行连等
{
// 先判断是否有属性在堆区，如果有先开释洁净
if (m_a != NULL)
{
delete m_a;
m_a = NULL;
}
m_a = new int(*p.m_a);
return *this;
}
int* m_a;
};
void test01()
{Person p1(18);
Person p2(209);
Person p3(9);
p2 = p1 = p3;
cout << *p1.m_a << endl;
cout << *p2.m_a << endl;
cout << *p3.m_a << endl;
}
int main()
{test01();
system("pause");
return 0;
}关系运算符重载
#include<iostream>
using namespace std;
#include<string>
class Person
{
public:
Person(string name, int age)
{
this->age = age;
this->name = name;
}
bool operator==(Person& p)
{if (this->age == p.age && this->name == p.name)
{return true;}
else {return false;}
}
bool operator!=(Person& p)
{if (this->age == p.age && this->name == p.name)
{return false;}
else {return true;}
}
string name;
int age;
};
void test01()
{Person p1("gouride", 19);
Person p2("gouride", 19);
if (p1 == p2) {cout << "p1 和 p2 雷同" << endl;}
else {cout << "p1 和 p2 不雷同" << endl;}
if (p1 != p2) {cout << "p1 和 p2 不雷同" << endl;}
else {cout << "p1 和 p2 雷同" << endl;}
}
int main()
{test01();
system("pause");
return 0;
}函数调用重载
仿函数
#include<iostream>
using namespace std;
#include<string>
class Myprint
{
public:
void operator()(string name)
{cout << name << endl;}
int operator()(int a,int b)
{return a + b;}
};
void test01()
{
Myprint myprint;
myprint("测试");
// 匿名对象调用
cout << Myprint()(4,6) << endl;
}
int main()
{test01();
system("pause");
return 0;
}正文完