[LeetCode] 905. Sort Array By Parity

Problem
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A.
You may return any answer array that satisfies this condition.
Example 1:
Input: [3,1,2,4]Output: [2,4,3,1]The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
Note:
1 <= A.length <= 50000 <= A[i] <= 5000
Solution
class Solution {
public int[] sortArrayByParity(int[] A) {
if (A == null || A.length < 2) return A;
int i = 0, j = 0;
while (j < A.length) {
while (i < j && A[i]%2 == 0) i++;
if (A[j]%2 == 0) {
int temp = A[i];
A[i] = A[j];
A[j] = temp;
i++;
}
j++;
}
return A;
}
}

评论

发表回复

您的邮箱地址不会被公开。 必填项已用 * 标注

这个站点使用 Akismet 来减少垃圾评论。了解你的评论数据如何被处理