[LeetCode] 905. Sort Array By Parity

39次阅读

共计 522 个字符,预计需要花费 2 分钟才能阅读完成。

Problem
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A.
You may return any answer array that satisfies this condition.
Example 1:
Input: [3,1,2,4]Output: [2,4,3,1]The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
Note:
1 <= A.length <= 50000 <= A[i] <= 5000
Solution
class Solution {
public int[] sortArrayByParity(int[] A) {
if (A == null || A.length < 2) return A;
int i = 0, j = 0;
while (j < A.length) {
while (i < j && A[i]%2 == 0) i++;
if (A[j]%2 == 0) {
int temp = A[i];
A[i] = A[j];
A[j] = temp;
i++;
}
j++;
}
return A;
}
}

正文完
 0