1,获取URL的参数,返回一个对象
getRequest() {
const url = location.search; //获取url中"?"符后的字串
let theRequest = new Object();
if (url.indexOf("?") != -1) {
let str = url.substr(1);
let strs = str.split("&");
for (let i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
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