Roles角色合约(次要为前面的保险公司C提供环境)
// SPDX-License-Identifier: 3.0 pragma solidity ^0.8.20; library Roles { struct Role { mapping (address => bool) bearer; } function has(Role storage role, address account) internal view returns (bool) { require(account != address(0), "Roles: account is the zero address"); return role.bearer[account]; }//查问增加的账户是否为空 function add(Role storage role, address account) internal { require(!has(role, account), "Roles: account already has role"); role.bearer[account] = true; }//减少账户 function remove(Role storage role, address account) internal { require(has(role, account), "Roles: account does not have role"); role.bearer[account] = false; }//删除账户}
}.AirlineV.sol航空公司合约
// SPDX-License-Identifier: 3.0 pragma solidity ^0.8.20; import "./Roles.sol"; contract AirlineV { using Roles for Roles.Role; Roles.Role private _airlineV;
首先申明两个事件(增删账户)
event airlineVAdded(address account); event airlineVRemoved(address account);
初始化合约(构造函数)
constructor (address airlineV) { _addairlineV(airlineV); }
创立润饰器 onlyairlineV(限度拜访权限时调用)
modifier onlyairlineV() { require( isairlineV(msg.sender),"airlineVRole: caller does not have the airlineV role"); _; }
结构isairlineV函数判断是否具备airlineV角色
function isairlineV(address account)public view returns(bool){ return _airlineV.has(account); }
结构两个增加航空公司的函数,用于合约外部调用(_addairlineV)和内部调用(addairlineV)
function _addairlineV(address account) internal { _airlineV.add(account); emit airlineVAdded(account); }
结构一个合约外部删除函数(_removeairlineV)和用户自行退出函(renounceairlineV)
function addairlineV(address account) public onlyairlineV{ _addairlineV(account);} function _removeairlineV(address account) internal { // _ai,.rlineV.remove(account); emit airlineVRemoved(account);}function renounceairlineV() public { _removeairlineV(msg.sender);}
}演示:输出账号,点击transact
应用部署的账号进行减少操作
如果应用oxAb8...则会报错
isairlineV进行判断账号是否为航空公司身份
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原文链接:https://blog.csdn.net/2302_77339802/article/details/131834020
文章起源:CSDN 博主「发愣...」
文章原题目:《solidity案例详解(三)飞机治理合约》旨在流传区块链相干技术,如有侵权请与咱们分割删除。