关于python:fastapi-如何在中间件中抛出-401

fastapi 如何在中间件中抛出异样？

chatGPT 给我的计划是：raise HTTPException(status_code=401, detail="Invalid token")

然而理论没用，客户端收到的还是 500

理论应该 return 一个 response

参考代码：

@app.middleware("http")async def get_user_id(request: Request, call_next):    from core.mysql.models import SessionTable    from core.mysql.models import SessionTable    from core.mysql.models import UserTable    from apps.user.schemas import User    from playhouse.shortcuts import model_to_dict    session_key = request.cookies.get("session_key")    if session_key:        try:            session: SessionTable | None = SessionTable.get_or_none(                session_key=session_key)            if session:                user_id = session.user_id                if user_id:                    request.state.user_id = user_id                    user: UserTable | None = UserTable.get_or_none(id=user_id)                    request.state.user = User(**model_to_dict(user))        except Exception as error:            logger.warning(error)    if not session_key or not request.state.get('user_id', None):        return Response(status_code=401, content='Invalid token')    response = call_next(request)    return response