关于前端:js获取url问号后参数

js实现获取url问号后参数，第一步封装办法获取?后所有字符，并依据&=符号获取单个或多个参数及参数值

getParams() {  var url = location.search;  var params = new Object();  if (url.indexOf("?") != -1) {    const str = url.substr(1);    const strs = str.split("&");    for (var i = 0; i < strs.length; i++) {      params[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);    }  }  return params;}

办法写好后间接调用办法获取url。其中 urlParams['参数名']，如果参数名写错会获取不到此参数值。例：http:172.17.10.0:8080?id=123&name=张三，应用：urlParams['id']，urlParams['name']

console.log(window.location.search)var urlParams = new Object();urlParams = this.getParams();this.id = urlParams['id'];   //要获取的参数名this.name = urlParams['name'];   //要获取的参数名console.log(this.id, this.name)