MySQL实现累加、累乘、累减、累除

table: TEST+-----------+---------+---------+| PARENT_ID | PART_ID | QUALITY |+-----------+---------+---------+|         1 |       1 |       2 ||         1 |       2 |       3 ||         1 |       3 |       2 ||         1 |       4 |       5 ||         2 |       2 |       3 ||         2 |       3 |       5 ||         2 |       4 |       7 |+-----------+---------+---------+

累加

最简略,用sum+over即可

SELECT    T.*,    SUM(T.QUALITY) OVER (PARTITION BY T.PARENT_ID ORDER BY T.PART_ID) RUNNING_QUALITYFROM    TEST T;

累乘

应用EXP(SUM(LN(字段))实现累乘,其余的和累加一样!

SELECT    T.*,    ROUND(EXP(SUM(LN(T.QUALITY)) OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID)),0) RUNNING_PRODFROM    TEST T;

累减

累减巧用负号!

(1)先用row_number排序

SELECT  T.*,  ROW_NUMBER() OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID) RNFROM TEST T
+-----------+---------+---------+----+| PARENT_ID | PART_ID | QUALITY | RN |+-----------+---------+---------+----+|         1 |       1 |       2 |  1 ||         1 |       2 |       3 |  2 ||         1 |       3 |       2 |  3 ||         1 |       4 |       5 |  4 ||         2 |       2 |       3 |  1 ||         2 |       3 |       5 |  2 ||         2 |       4 |       7 |  3 |+-----------+---------+---------+----+

(2)当RN=1时,保留第一位的数字,其余的全副取负号,这样就能够实现累减了!

SELECT    T.PARENT_ID,    T.PART_ID,    T.QUALITY,    SUM(if(T.RN=1,T.QUALITY,-T.QUALITY)) OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID) RUNNING_PRODFROM    (        SELECT            T.*,            ROW_NUMBER() OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID) RN        FROM            TEST T) T;

累除

和累减相似,只不过这里要把非第一位的数字,取对数后再取负号,这样通过sum和exp就相当于做除法啦!

SELECT    T.PARENT_ID,    T.PART_ID,    T.QUALITY,    round(EXP(SUM(if(RN=1,LN(T.QUALITY),-LN(T.QUALITY))) OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID)),2) RUNNING_PRODFROM    (        SELECT            T.*,            ROW_NUMBER() OVER(PARTITION BY T.PARENT_ID ORDER BY T.PART_ID) RN        FROM            TEST T)T;

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