关于前端:通过子节点找到父节点完整路径

 const getTreeIds = (tree: any[], nodeId: any, config: {}) => {//tree指标树，nodeId节点id    const { children = 'cityList', id = 'adCode' } = config || {}    const toFlatArray = (tree: any[], parentId: never[]) => {      return tree.reduce((t: any, _: Record<string, any>) => {        const child = _[children]        return [          ...t,          parentId ? { ..._, parentId } : _,          ...(child && child.length ? toFlatArray(child, _[id]) : [])]      }, [])    }    const getIds = (flatArray: any[]) => {      let ids = [nodeId]      let child = flatArray.find((_: Record<string, any>) => _[id] === nodeId)      while (child && child.parentId) {        ids = [child.parentId, ...ids]        // eslint-disable-next-line @typescript-eslint/no-loop-func        child = flatArray.find((_: Record<string, any>) => _[id] === child.parentId)      }      return ids    }    return getIds(toFlatArray(tree, []))  }