理论应用

位运算只可使用于整数,对于 float 和 double 不行。

  • WebGL 游戏数据处理
  • WebSockets、AJAX、Fetch、WebRTC 服务通信
  • WebUSB、WebAudio 硬件通信
  • Crypto 加密算法

1. 一些根本用法

位运算性能示例
x >> 1去掉最初一位101101->10110
x << 1在最初加一个0101101->1011010
x << 1 | 1在最初加一个1101101->1011011
x | 1把最初一位变成1101100->101101
x & -2把最初一位变成0101101->101100
x ^ 1最初一位取反101101->101100
x | (1 << (k-1))把右数第k位变成1101001->101101,k=3
x & ~ (1 << (k-1))把右数第k位变成0101101->101001,k=3
x ^(1 <<(k-1))右数第k位取反101001->101101,k=3
x & 7取末三位1101101->101
x & (1 << k-1)取末k位1101101->1101,k=5
x >> (k-1) & 1取右数第k位1101101->1,k=4
x | ((1 << k)-1)把末k位变成1101001->101111,k=4
x ^ (1 << k-1)末k位取反101001->100110,k=4
x & (x+1)把左边间断的1变成0100101111->100100000
x | (x+1)把右起第一个0变成1100101111->100111111
x | (x-1)把左边间断的0变成111011000->11011111
(x ^ (x+1)) >> 1取左边间断的1100101111->1111
x & -x去掉右起第一个1的右边100101000->1000
x&0x7F取末7位100101000->101000
x& ~0x7F是否小于127001111111 & ~0x7F->0
x & 1判断奇偶00000111&1->1
// 取正数console.log(~4 + 1); // -4// 舍弃小数console.log(~~1.5); // 1// 取模(余数)// i % 4 === i & (4 - 1)console.log(1 % 4, 1 & 3); // 1 1

2. 替换两数

int swap(int a, int b){    if (a != b)    {        a ^= b;        b ^= a;        a ^= b;    }}

3. 求绝对值

int abs(int a){    int i = a >> 31;    return ((a ^ i) - i);}

4. 二分查找 32 位整数前导 0 个数

int nlz(unsigned x){   int n;   if (x == 0) return(32);   n = 1;   if ((x >> 16) == 0) {n = n +16; x = x <<16;}   if ((x >> 24) == 0) {n = n + 8; x = x << 8;}   if ((x >> 28) == 0) {n = n + 4; x = x << 4;}   if ((x >> 30) == 0) {n = n + 2; x = x << 2;}   n = n - (x >> 31);   return n;}

5. 二进制逆序

int reverse_order(int n){  n = ((n & 0xAAAAAAAA) >> 1) | ((n & 0x55555555) << 1);  n = ((n & 0xCCCCCCCC) >> 2) | ((n & 0x33333333) << 2);  n = ((n & 0xF0F0F0F0) >> 4) | ((n & 0x0F0F0F0F) << 4);  n = ((n & 0xFF00FF00) >> 8) | ((n & 0x00FF00FF) << 8);  n = ((n & 0xFFFF0000) >> 16) | ((n & 0x0000FFFF) << 16);  return n;}

6. 二进制中 1 的个数

 unsigned int BitCount_e(unsigned int value) {    unsigned int count = 0;    // 解释下上面这句话代码,这句话求得两两相加的后果,例如 11 01 00 10    // 11 01 00 10 = 01 01 00 00 + 10 00 00 10,即由奇数位和偶数位相加而成    // 记 value = 11 01 00 10,high_v = 01 01 00 00, low_v = 10 00 00 10    // 则 value = high_v + low_v,high_v 右移一位得 high_v_1,    // 即 high_v_1 = high_v >> 1 = high_v / 2    // 此时 value 能够示意为 value = high_v_1 + high_v_1 + low_v,    // 可见 咱们须要 high_v + low_v 的和即等于 value - high_v_1    // 写简略点就是 value = value & 0x55555555 + (value >> 1) & 0x55555555;    value = value - ((value >> 1) & 0x55555555);    // 之后的就好了解了    value = (value & 0x33333333) + ((value >> 2) & 0x33333333);    value = (value & 0x0f0f0f0f) + ((value >> 4) & 0x0f0f0f0f);    value = (value & 0x00ff00ff) + ((value >> 4) & 0x00ff00ff);    value = (value & 0x0000ffff) + ((value >> 8) & 0x0000ffff);    return value;    // 另一种写法,原理一样,起因在最初一种解法中有提到    //value = (value & 0x55555555) + (value >> 1) & 0x55555555;    //value = (value & 0x33333333) + ((value >> 2) & 0x33333333);    //value = (value & 0x0f0f0f0f) + ((value >> 4) & 0x0f0f0f0f);    //value = value + (value >> 8);    //value = value + (value >> 16);    //return (value & 0x0000003f);}

7. 字符串和字节互转

function stringToByte(str: string) {  const bytes = [];  let c: number;  const len = str.length;  for (let i = 0; i < len; i++) {    c = str.charCodeAt(i);    if (c >= 0x010000 && c <= 0x10ffff) {      bytes.push(((c >> 18) & 0x07) | 0xf0);      bytes.push(((c >> 12) & 0x3f) | 0x80);      bytes.push(((c >> 6) & 0x3f) | 0x80);      bytes.push((c & 0x3f) | 0x80);    } else if (c >= 0x000800 && c <= 0x00ffff) {      bytes.push(((c >> 12) & 0x0f) | 0xe0);      bytes.push(((c >> 6) & 0x3f) | 0x80);      bytes.push((c & 0x3f) | 0x80);    } else if (c >= 0x000080 && c <= 0x0007ff) {      bytes.push(((c >> 6) & 0x1f) | 0xc0);      bytes.push((c & 0x3f) | 0x80);    } else {      bytes.push(c & 0xff);    }  }  return bytes;}function byteToString(arr: any) {  if (typeof arr === "string") {    return arr;  }  let str = "";  const _arr = arr;  for (let i = 0; i < _arr.length; i++) {    const one = _arr[i].toString(2),      v = one.match(/^1+?(?=0)/);    if (v && one.length == 8) {      const bytesLength = v[0].length;      let store = _arr[i].toString(2).slice(7 - bytesLength);      for (let st = 1; st < bytesLength; st++) {        store += _arr[st + i].toString(2).slice(2);      }      str += String.fromCharCode(parseInt(store, 2));      i += bytesLength - 1;    } else {      str += String.fromCharCode(_arr[i]);    }  }  return str;}

charCodeAt 获取到值的范畴 0 ~ 65536 ,按 8 bits 切成 4 个字节。

8. 应用左移运算符 << 迅速得出 2 的次方

1 << 2; // 4, 即 2的2次方1 << 10; // 1024, 即 2的10次方// 然而要留神应用场景, 非1的数字,会扭转首位的正负a = 2e9; // 2000000000a << 1; // -294967296

9. 应用 ^ 切换变量 0 或 1

// --- before ---// if 判断if (toggle) {  toggle = 0;} else {  toggle = 1;}// 三目运算符togle = toggle ? 0 : 1;// --- after ---toggle ^= 1;

10. 应用~>><<>>>|来取整

相当于应用了 Math.floor()

console.log(~~11.71); // 11console.log(11.71 >> 0); // 11console.log(11.71 << 0); // 11console.log(11.71 | 0); // 11console.log(11.71 >>> 0); // 11

11. 应用^判断符号是否雷同

(a ^ b) >= 0; //  true 雷同; false 不雷同  复制代码

11. 应用 A + 0.5 | 0 来代替 Math.round()

如果是正数,用 A - 0.5 | 0

12. 应用&, >>, |来实现 rgb 值和 16 进制色彩值之间的转换

/** * 16进制色彩值转RGB * @param  {String} hex 16进制色彩字符串 * @return {String}     RGB色彩字符串 */function hexToRGB(hex) {  var hexx = hex.replace("#", "0x");  var r = hexx >> 16;  var g = (hexx >> 8) & 0xff;  var b = hexx & 0xff;  return `rgb(${r}, ${g}, ${b})`;}/** * RGB色彩转16进制色彩 * @param  {String} rgb RGB进制色彩字符串 * @return {String}     16进制色彩字符串 */function RGBToHex(rgb) {  var rgbArr = rgb.split(/[^\d]+/);  var color = (rgbArr[1] << 16) | (rgbArr[2] << 8) | rgbArr[3];  return "#" + color.toString(16);}// -------------------------------------------------hexToRGB("#ffffff"); // 'rgb(255,255,255)'RGBToHex("rgb(255,255,255)"); // '#ffffff'

13. base64 转 blob

// 转换为 blob 间接传输 临时无用export const dataURItoBlob = (dataURI: string) => {  // convert base64 to raw binary data held in a string  // doesn't handle URLEncoded DataURIs  var byteString = atob(dataURI.split(",")[1]);  // separate out the mime component  var mimeString = dataURI    .split(",")[0]    .split(":")[1]    .split(";")[0];  // write the bytes of the string to an ArrayBuffer  var ab = new ArrayBuffer(byteString.length);  var ia = new Uint8Array(ab);  for (var i = 0; i < byteString.length; i++) {    ia[i] = byteString.charCodeAt(i);  }  return new window.Blob([ia], { type: mimeString });};export const base64ToFile = (dataurl: string, filename: string) => {  var arr = dataurl.split(","),    // @ts-ignore    mime = arr[0].match(/:(.*?);/)[1],    bstr = atob(arr[1]),    n = bstr.length,    u8arr = new Uint8Array(n);  while (n--) {    u8arr[n] = bstr.charCodeAt(n);  }  return new File([u8arr], filename, { type: mime });};

14. Base64 库

export const Base64 = {  // private property  _keyStr: "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",  /**   * 应用Base64编码字符串   *   * @param { string } input 待编码内容   * @returns { string }   */  encode: (input) => {    let output = "";    let chr1, chr2, chr3, enc1, enc2, enc3, enc4;    let i = 0;    input = Base64._utf8_encode(input);    while (i < input.length) {      chr1 = input.charCodeAt(i++);      chr2 = input.charCodeAt(i++);      chr3 = input.charCodeAt(i++);      enc1 = chr1 >> 2;      enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);      enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);      enc4 = chr3 & 63;      if (isNaN(chr2)) {        enc3 = enc4 = 64;      } else if (isNaN(chr3)) {        enc4 = 64;      }      output =        output +        Base64._keyStr.charAt(enc1) +        Base64._keyStr.charAt(enc2) +        Base64._keyStr.charAt(enc3) +        Base64._keyStr.charAt(enc4);    }    return output;  },  /**   * 解码Base64字符串   *   * @param { string } input 待解码Base64字符串   * @returns   */  decode: (input) => {    let output = "";    let chr1, chr2, chr3, enc1, enc2, enc3, enc4;    let i = 0;    input = input.replace(/[^A-Za-z0-9\+\/\=]/g, "");    while (i < input.length) {      enc1 = Base64._keyStr.indexOf(input.charAt(i++));      enc2 = Base64._keyStr.indexOf(input.charAt(i++));      enc3 = Base64._keyStr.indexOf(input.charAt(i++));      enc4 = Base64._keyStr.indexOf(input.charAt(i++));      chr1 = (enc1 << 2) | (enc2 >> 4);      chr2 = ((enc2 & 15) << 4) | (enc3 >> 2);      chr3 = ((enc3 & 3) << 6) | enc4;      output = output + String.fromCharCode(chr1);      if (enc3 != 64) {        output = output + String.fromCharCode(chr2);      }      if (enc4 != 64) {        output = output + String.fromCharCode(chr3);      }    }    output = Base64._utf8_decode(output);    return output;  },  /**   * private method for UTF-8 encoding   *   * @private   * @param { string } string   * @returns   */  _utf8_encode: (string) => {    string = string.replace(/\r\n/g, "\n");    let utfText = "";    for (let n = 0; n < string.length; n++) {      const c = string.charCodeAt(n);      if (c < 128) {        utfText += String.fromCharCode(c);      } else if (c > 127 && c < 2048) {        utfText += String.fromCharCode((c >> 6) | 192);        utfText += String.fromCharCode((c & 63) | 128);      } else {        utfText += String.fromCharCode((c >> 12) | 224);        utfText += String.fromCharCode(((c >> 6) & 63) | 128);        utfText += String.fromCharCode((c & 63) | 128);      }    }    return utfText;  },  /**   * private method for UTF-8 decoding   *   * @private   * @param {string} utfText   * @returns   */  _utf8_decode: (utfText) => {    let string = "";    let i = 0;    let c,      c2,      c3 = 0;    while (i < utfText.length) {      c = utfText.charCodeAt(i);      if (c < 128) {        string += String.fromCharCode(c);        i++;      } else if (c > 191 && c < 224) {        c2 = utfText.charCodeAt(i + 1);        string += String.fromCharCode(((c & 31) << 6) | (c2 & 63));        i += 2;      } else {        c2 = utfText.charCodeAt(i + 1);        c3 = utfText.charCodeAt(i + 2);        string += String.fromCharCode(          ((c & 15) << 12) | ((c2 & 63) << 6) | (c3 & 63)        );        i += 3;      }    }    return string;  },};

15. crypto-js 库

https://github.com/brix/crypt...

其它

(1)判断奇偶

只有依据最未位是 0 还是 1 来决定,为 0 就是偶数,为 1 就是奇数。因而能够用if ((i & 1) === 0)代替if (i % 2 === 0)来判断 a 是不是偶数。

(2)清零

如果想将一个单元清零,即便其全副二进制位为 0,只有与一个各位都为零的数值相与,后果为零。

(3)是否 2 的 n 次幂

// (x & x - 1) === 0console.log((2 & (2 - 1)) === 0); // true

(4)求平均值避免溢出

// 求平均值,防溢出function avg(x, y) {  return (x & y) + ((x ^ y) >> 1);}

参考

javascript 位运算技巧