# key 和 value 个数统一x = [1,2,3,4,5]y = ['a','b','c','d','e']res = dict(zip(y,x))print(res)print("===================")# key 和 value 个数不统一## key多x = [1,2]y = ['a','b','c']res = dict(zip(y,x))print(res)print("===================")## key少x = [1,2,3,4]y = ['a','b','c']res = dict(zip(y,x))print(res)print("===================")# 将字符串转换为列表temp_str = "['肯德基','麦当劳','华莱士']"temp_list = ast.literal_eval(temp_str)print(temp_list)print(type(temp_list))输入后果:
{'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
{'a': 1, 'b': 2}
{'a': 1, 'b': 2, 'c': 3}
['肯德基', '麦当劳', '华莱士']
<class 'list'>
原文链接：https://blog.csdn.net/qq_1724...