关于go:go-使用slice或者map-来聚合-一一对应的关系数据

最近在写一个需要如下，有5中金币类型，每种金币类型，有对应的金币数，以及金币支付下限。
原来的代码，是如下写法：

//金币类型const CoinType1 = 1const CoinType2 = 2const CoinType3 = 3const CoinType4 = 4const CoinType5 = 5//金币类型 对应的 金币数const CoinType1CoinNum = 11const CoinType2CoinNum = 12const CoinType3CoinNum = 13const CoinType4CoinNum = 14const CoinType5CoinNum = 15//金币类型 对应的 金币支付下限const CoinType1LimitTimes = 101const CoinType2LimitTimes = 102const CoinType3LimitTimes = 103const CoinType4LimitTimes = 104const CoinType5LimitTimes = 105

随着金币类型的减少，每次，都要减少三个变量，且获取的时候，还要对应关系，想到用
k，v构造来优化

变量太多，不利于保护，能不加新的，最好不加

计划一：slice 来示意一一对应

//金币类型const CoinType1 = 1const CoinType2 = 2const CoinType3 = 3const CoinType4 = 4const CoinType5 = 5var CoinNum = []int{    CoinType1: 11,    CoinType2: 12,    CoinType3: 13,    CoinType4: 14,    CoinType5: 15,}var CoinLimitTimes = []int{    CoinType1: 101,    CoinType2: 102,    CoinType3: 103,    CoinType4: 104,    CoinType5: 105,}

计划二：map 来示意一一对应

//金币类型const CoinType1 = 1const CoinType2 = 2const CoinType3 = 3const CoinType4 = 4const CoinType5 = 5var CoinNum = map[int]int{    CoinType1: 11,    CoinType2: 12,    CoinType3: 13,    CoinType4: 14,    CoinType5: 15,}var CoinLimitTimes = map[int]int{    CoinType1: 101,    CoinType2: 102,    CoinType3: 103,    CoinType4: 104,    CoinType5: 105,}