关于javascript:算法leetcode-704-二分查找

https://leetcode.cn/problems/...

解题思路

1. 确定左右
2. 计算两头
3. 两头大于指标则示意左边只会更大于指标，舍弃
4. 两头小于指标则示意右边只会更小于指标，舍弃
5. 批改左或右为两头

/*** @param {number[]} nums* @param {number} target* @return {number}*/var search = function(nums, target) {   if(nums === null || nums.length === 0) {       return -1   }   let left = 0   let right = nums.length - 1   while(left <= right) {       let mid = left + Math.floor((right - left) / 2)       if(nums[mid] === target) {           return mid       }       else if(nums[mid] > target) {           right = mid - 1       }       else if(nums[mid] < target) {           left = mid + 1       }   }   return -1};