关于学习:给定两个数组-编写一个函数计算交集部分-返回的数组不重复

// 办法一：

    const intersection = (arr,arr1) => {                let obj = {} , res = [];                arr.forEach(item => {                    obj[item] = true;                })                arr1.forEach(item => {                    if(obj[item]){                        res.push(item)                        obj[item] = false                    }                })                return  res    }

// 办法二:

const intersection = (arr,arr1) => [...new Set (arr.filter(item => arr1.includes(item)))]