1.多表父子级关系利用流来解决
private List<AddressInfo> children;List<AddressInfo> collect1 = addressInfo.stream().map(m1 -> {List<AddressInfo> collect = addressInfo.stream().filter( m2 -> Objects.equals(m1.getId(), m2.getPId())).collect(Collectors.toList());m1.setChildren(collect);return m1; }).collect(Collectors.toList());
阐明:m1 父级信息 m2 子级信息
2单表父子级关系解决
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>(); /** * 3.循环解决全副数据,转为父子级对象 */ for (AddressInfo vo : addressInfo) { Map<String, Object> map = new HashMap<String, Object>(8); if (vo.getPId() == 0) { map.put("children", getChildren(addressInfo, vo.getId())); map.put("pId", vo.getPId()); 寄存子级数据 list.add(map); } } PageInfo<AddressInfo> pageInfo = new PageInfo<>(addressInfo); return success(list, pageInfo.getTotal());}public List<Map<String, Object>> getChildren(List<AddressInfo> data, Integer wzflid) { /** * 1.对数据校验解决 */ List<Map<String, Object>> list = new ArrayList<Map<String, Object>>(); if (data == null || data.size() == 0 || wzflid == null) { return list; } /** * 2.遍历匹配父子级关系数据 */ for (AddressInfo vo : data) { Map<String, Object> map = new HashMap<String, Object>(8); if (wzflid.equals(vo.getPId())) { map.put("pId", vo.getPId()); list.add(map); } } return list;}