转载自 https://blog.csdn.net/qq_3383...

一、报错信息
Caused by: Column 'xxxx' in where clause is ambiguous

二、报错起因
表 person 和 表 class 都有字段 id 和 name ,所以要给它们减少别名来进行辨别。

PersonVOMapper.java

public interface PersonVOMapper extends BaseMapper<PersonVO> {    List<PersonVO> getPersonVOList(@Param(Constants.WRAPPER) Wrapper<PersonVO> queryWrapper);    }PersonVOMapper.xml<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE mapper PUBLIC "-//mybatis.org//DTD Mapper 3.0//EN" "http://mybatis.org/dtd/mybatis-3-mapper.dtd"><mapper namespace="com.sionas.mapper.PersonVOMapper">    <select id="getPersonVOList" resultType="com.sionas.domain.PersonVO">        SELECT            p.id AS personId,            p.name AS personName,            p.sex,            p.age,            c.id AS classId,            c.name AS className        FROM            person p        LEFT JOIN class c ON c.id = p.class_id;        ${ew.customSqlSegment}    </select></mapper>

${ew.customSqlSegment} 是Mybatis Plus的动静条件结构器的最终条件SQL

PersonServiceImpl.java

LambdaQueryWrapper<PersonVO> wrapper = new LambdaQueryWrapper<>();wrapper.like(PersonVO::getPersonName, keyword)       .or().like(PersonVO::getClassName, keyword);List<PersonVO> list = personVOMapper.getPersonVOList(wrapper);

此时会报错 Column ‘name’ in where clause is ambiguous,意思是 where子句中的列“name”是不明确的。

起因: 多表查问后字段 name 是反复的,查问后果集中含有两个 name 不晓得是哪一个才是要查问的。条件语句是针对查问后果集的,所以此时的 字段重命名有效。

三、解决办法
办法一:
应用明确的字段名称 表名.字段名

LambdaQueryWrapper<PersonVO> wrapper = new LambdaQueryWrapper<>();wrapper.like("p.name", keyword)       .or().like("c.name", keyword);List<PersonVO> list = personVOMapper.getPersonVOList(wrapper);

办法二:
把查问后果作为子查问,而后再减少条件语句

    SELECT        *    FROM (        SELECT            p.id AS personId,            p.name AS personName,            p.sex,            p.age,            c.id AS classId,            c.name AS className        FROM            person p        LEFT JOIN class c ON c.id = p.class_id    ) AS result    ${ew.customSqlSegment}

能够间接应用如下形式进行查问而不须要补全表名:

LambdaQueryWrapper<PersonVO> wrapper = new LambdaQueryWrapper<>();wrapper.like(PersonVO::getPersonName, keyword)       .or().like(PersonVO::getClassName, keyword);List<PersonVO> list = personVOMapper.getPersonVOList(wrapper);

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原文链接:https://blog.csdn.net/qq_3383...