C语言实现三子棋（通过数组）
须要蕴含的头文件

include <stdio.h>

include <stdlib.h>

include <time.h>

创立一个全局数组
因为如果数组大小变动，游戏规则和实现思路都会有很大的变动，所以不进行宏定义常量来定义数组
char board3;
设计主程序框架
game()函数为游戏过程框架
int main()
{

do{    int i = 0;    printf("1.Start the game\n");    printf("2.Quit the game\n");    printf("Please enter your options->");    scanf("%d", &i);    switch (i)    {        case 1:            game();    //game()函数为游戏过程框架            break;        case 2:            return 0;        default:            printf("Input error,please enter again!\n");            break;    }} while(1);

}
设计游戏过程框架
void game()
{

initBoard();srand((unsigned)time(NULL));    //生成随机种子，前面须要生成随机坐标char temp = ' ';                //定义一个字符变量，用于接管前面判断函数返回值，用于决定游戏输赢do{    printBoard();           //打印棋盘的函数    userPlay();             //玩家下棋的函数    temp = judge();         //判断游戏是否分出输赢    if (temp != ' ')        break;    robotPlay();            //电脑下棋的函数    temp = judge();} while (temp == ' ');printBoard();switch (temp){    case '@':        printf("User WIN!\n");        break;    case '$':        printf("Bobot WIN!\n");        break;    case '*':        printf("Dogfall !\n");        break;    dafault:        break;}

}
设计棋盘款式
有趣味的能够搞的更加花里胡哨，这里草草了事，呸，简略设计一下 哈
//##########
// | |
//_|_|_
// | |
//_|_|_
// | |
//##########
打印棋盘
重点就在这了，棋盘设计的再牛逼，也得能打印进去才行
这里棋盘设计的比拟繁难，打印起来也比较简单，要害是思路要清晰
void printBoard()
{

printf("##########\n");int i = 0,j = 0;for (i = 0; i < 3; i++){    for (j = 0; j < 3; j++)    {        if (j != 2)        {            printf("%c|",board[i][j]);        }        else            printf("%c\n",board[i][j]);    }    if (i != 2)        printf("_|_|_\n");}printf("##########\n");

}
玩家下棋
自己习惯用界面编程的坐标系示意坐标，因而上面赋值时横坐标和纵坐标倒过去了
void userPlay()
{

printf("Please enter coordinates->");int x = 0,y = 0;while(1){    scanf("%d %d", &x, &y);    if (x > 0 && x < 4 && y > 0 && y < 4)    {                if (board[y - 1][x - 1] == ' ')        {            board[y - 1][x - 1] = '@';            break;        }        else            printf("There are chess pieces here,please enter again!->");    }    else        printf("Input error,please enter again!->");}

}

电脑下棋
这里要害是 要生成可行的坐标，以及随机数的生成
void robotPlay()
{

int i = 0, j = 0;while (1){    i = rand() % 3;    j = rand() % 3;    if (board[i][j] == ' ')    {        board[i][j] = '$';        break;    }}

}
判断游戏输赢
这里就到了最难剖析的一部分了
废话不多说，间接看代码
char judge()
{

int i = 0, j = 0;    //判断两条对角线    对i j 的值不做带动，所以放在后面if (board[i][j] == board[i + 1][j + 1] && board[i][j] == board[i + 2][j + 2] && board[i][j] != ' ')    return board[i][j];if (board[i][j + 2] == board[i + 1][j + 1] && board[i][j + 2] == board[i + 2][j] && board[i][j] != ' ')    return board[i][j + 2];    //顺次判断三行、三列for (i = 0,j = 0; j < 3; j++){    if (board[i][j] == board[i + 1][j] && board[i][j] == board[i + 2][j] && board[i][j] != ' ')        return board[i][j];}for (i = 0,j = 0; i < 3; i++){    if (board[i][j] == board[i][j + 1] && board[i][j] == board[i][j + 2] && board[i][j] != ' ')        return board[i][j];}    //判断棋盘是否满了（平局）for (i = 0; i < 3; i++){    for (j = 0;j < 3; j++)    {        if (board[i][j] == ' ')            return board[i][j];    }}    //如果没呈现以上状况，轻易返回一个不同符号，使游戏持续进行return '*';

}