关于javascript:如何清除url中指定参数并返回url

export function deleteUrlQueryByName(param) {  const reg = new RegExp('(^|&)' + param + '=([^&]*)(&|$)');  const r =    window.location.search.substr(1).match(reg) ||    window.location.hash      .substring(window.location.hash.search(/\?/) + 1)      .match(reg);  if (r != null) {    return window.location.href.replace(      `${param}=${decodeURIComponent(r[2])}`,      '',    );  }  return window.location.href;}