关于php:如何在Php中获得一个Final类的Protected的static成员属性

<?php final class ConstantOne {  static protected $ERRNO_OK;  static protected function init_ERRNO_OK() {    return 0;  }  static protected function init_ErrorMsg() {    return array(      0 => "OK",    );  }}

请答题：

如何获取'0'?

谬误形式1

class test extends ConstantOne{}ECHO test::init_ERRNO_OK();

形式1起因：

PHP Fatal error: Class test may not inherit from final class (ConstantOne)

谬误形式2

var_dump(ConstantOne::init_ErrorMsg());

形式2起因：

PHP Fatal error: Uncaught Error: Call to protected method ConstantOne::init_ErrorMsg()

思考

staitc的话，我能够不实例化就能够调用，protected的话，能够实例化本类或者父类调用，然而要害是还有个final润饰。Final润饰的类不能被继承，所以只能本类调用，未实例的类调用static的办法又说是因为protected的。static实质是类的办法，

解决思路

/** * Base class for constant Management */abstract class BaseConstant{    /**     * Don't instanciate this class     */    protected function __construct() {}    /**     * Get a constant value     * @param string $constant     * @return mixed     */    public static function get($constant)    {        if(is_null(static::$$constant))        {            // echo sprintf('static::init_%s', $constant);            static::$$constant = call_user_func(                    sprintf('static::init_%s', $constant)                );        }        return static::$$constant;    }}final class ConstantTwo extends BaseConstant {  static protected $ERRNO_OK;  static protected function init_ERRNO_OK() {    return 100;  }  static protected function init_ErrorMsg() {    return array(      100 => "OK",    );  }//以下这也也能够  public static function outOK (){      echo static::init_ERRNO_OK();  }}echo ConstantTwo::get('ERRNO_OK');echo ConstantTwo::outOK();