???? 前言

大家好呀,我是毛小悠,能够叫我二毛,在家中排行老二,是一名前端开发工程师。

本系列文章旨在通过练习来进步JavaScript的能力,一起欢快的做题吧。????????????

以下每道题,二毛我都有尝试做一遍。倡议限时训练,比方限定为半小时,如果半小时内想不进去,能够联合文章开端的参考答案来思考。

能够在下方评论区留言或者加我的微信:code_maomao。期待你的到来。

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???? 题目1:用函数计算

这次咱们要应用函数编写计算并取得后果。让咱们看一些例子:

seven(times(five())); // must return 35four(plus(nine())); // must return 13eight(minus(three())); // must return 5six(dividedBy(two())); // must return 3

要求:

  • 每个数字必须有一个函数,范畴从0(“零”)到9(“ 9”)
  • 以下每个数学运算必须具备一个函数:加,减,乘,除(divided_by在Ruby和Python中)
  • 每次计算仅由一个操作和两个数字组成
  • 最外层的函数代表左操作数,最内层的函数代表右操作数
  • 除法应为整体除法。例如,应返回2,而不是2.666666...
eight(dividedBy(three()));

习题代码

function zero() {}function one() {}function two() {}function three() {}function four() {}function five() {}function six() {}function seven() {}function eight() {}function nine() {}function plus() {}function minus() {}function times() {}function dividedBy() {}

???? 题目2:RGB到十六进制转换

rgb性能不残缺。把RGB十进制值变为十六进制示意模式。RGB的无效十进制转换0-255。任何超出该范畴的值都必须四舍五入为最靠近的有效值。留神:您的答案应始终为6个字符长,带有3个字符的#FFF速记在这里不起作用。

以下是预期输入值的示例:

rgb(255, 255, 255) // returns FFFFFFrgb(255, 255, 300) // returns FFFFFFrgb(0,0,0) // returns 000000rgb(148, 0, 211) // returns 9400D3

习题代码:

rgb(r,g,b){}

???? 题目3:谁喜爱呢?

您可能从Facebook和其余页面晓得“喜爱”机制。

实现一个函数likes :: [String] -> String

likes [] -- must be "no one likes this"likes ["Peter"] -- must be "Peter likes this"likes ["Jacob", "Alex"] -- must be "Jacob and Alex like this"likes ["Max", "John", "Mark"] -- must be "Max, John and Mark like this"likes ["Alex", "Jacob", "Mark", "Max"] -- must be "Alex, Jacob and 2 others like this"

对于4个或更多的名称,数字and 2 others

习题代码

function likes(names) {  // TODO}

答案

???? 题目1的答案

参考答案1:

var n = function(digit) {  return function(op) {    return op ? op(digit) : digit;  }};var zero = n(0);var one = n(1);var two = n(2);var three = n(3);var four = n(4);var five = n(5);var six = n(6);var seven = n(7);var eight = n(8);var nine = n(9);function plus(r) { return function(l) { return l + r; }; }function minus(r) { return function(l) { return l - r; }; }function times(r) { return function(l) { return l * r; }; }function dividedBy(r) { return function(l) { return l / r; }; }

参考答案2:

function zero(func)   { return func ? func(0) : 0; };function one(func)    { return func ? func(1) : 1; };function two(func)    { return func ? func(2) : 2; };function three(func)  { return func ? func(3) : 3; };function four(func)   { return func ? func(4) : 4; };function five(func)   { return func ? func(5) : 5; };function six(func)    { return func ? func(6) : 6; };function seven(func)  { return func ? func(7) : 7; };function eight(func)  { return func ? func(8) : 8; };function nine(func)   { return func ? func(9) : 9; };function plus( b )      { return function( a ) { return a + b; }; };function minus( b )     { return function( a ) { return a - b; }; };function times( b )     { return function( a ) { return a * b; }; };function dividedBy( b ) { return function( a ) { return a / b; }; };

参考答案3:

['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'].forEach(function (name, n) {  this[name] = function (f) { return f ? f(n) : n }});function plus(n)      { return function (a) { return a + n } }function minus(n)     { return function (a) { return a - n } }function times(n)     { return function (a) { return a * n } }function dividedBy(n) { return function (a) { return a / n } }

参考答案4:

'zero one two three four five six seven eight nine'.split(' ').forEach(  (mth, num) => this[mth] = (f = val => val) => f(num) )let plus      = (r) => (l) => l + rlet minus     = (r) => (l) => l - rlet times     = (r) => (l) => l * rlet dividedBy = (r) => (l) => l / r

参考答案5:

const  id = x => x,  number = x => (f = id) => f(x),  [zero, one, two, three, four, five, six, seven, eight, nine] =    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9].map(number),  plus = x => y => y + x,  minus = x => y => y - x,  times = x => y => y * x,  dividedBy = x => y => y / x;

???? 题目2的答案

参考答案1:

function rgb(r, g, b){  return toHex(r)+toHex(g)+toHex(b);}function toHex(d) {    if(d < 0 ) {return "00";}    if(d > 255 ) {return "FF";}    return  ("0"+(Number(d).toString(16))).slice(-2).toUpperCase()}

参考答案2:

function rgb(r, g, b){  return [r,g,b].map(function(x) {    return ('0'+Math.max(0, Math.min(255, x)).toString(16)).slice(-2);  }).join('').toUpperCase();}

参考答案3:

function rgb(r, g, b){  function toHex(a) {     if (a <= 0) return '00';    else if (a >= 255) return 'FF';    else return a.toString(16).toUpperCase();  }  return toHex(r) + toHex(g) + toHex(b);}

参考答案4:

const rgb = (r, g, b) => toHex(r) + toHex(g) + toHex(b);function toHex(numb) {  if (numb <= 0)   return '00';  if (numb > 255)  return 'FF';  return numb.toString(16).toUpperCase();}

参考答案5:

let rgb = (r, g, b) => [r,g,b].map( (item) => item>=255 ? 'FF' : item<=0 ? '00' : item.toString(16).toUpperCase()).join('')

???? 题目3的答案

参考答案1:

function likes(names) {  names = names || [];  switch(names.length){    case 0: return 'no one likes this'; break;    case 1: return names[0] + ' likes this'; break;    case 2: return names[0] + ' and ' + names[1] + ' like this'; break;    case 3: return names[0] + ', ' + names[1] + ' and ' + names[2] + ' like this'; break;    default: return names[0] + ', ' + names[1] + ' and ' + (names.length - 2) + ' others like this';  }}

参考答案2:

function likes(names) {  return {    0: 'no one likes this',    1: `${names[0]} likes this`,     2: `${names[0]} and ${names[1]} like this`,     3: `${names[0]}, ${names[1]} and ${names[2]} like this`,     4: `${names[0]}, ${names[1]} and ${names.length - 2} others like this`,   }[Math.min(4, names.length)]}

参考答案3:

function likes (names) {  var templates = [    'no one likes this',    '{name} likes this',    '{name} and {name} like this',    '{name}, {name} and {name} like this',    '{name}, {name} and {n} others like this'  ];  var idx = Math.min(names.length, 4);    return templates[idx].replace(/{name}|{n}/g, function (val) {    return val === '{name}' ? names.shift() : names.length;  });}

参考答案4:

function likes(names) {  if(names.length === 0) return "no one likes this";  if(names.length === 1) return names[0] + " likes this";  if(names.length === 2) return names[0] + " and " + names[1] + " like this";  if(names.length === 3) return names[0] + ", " + names[1] + " and " + names[2] + " like this";  return names[0] + ", " + names[1] + " and " + (names.length - 2) + " others like this";}

参考答案5:

function likes(names) {  switch(names.length){    case 0:      return "no one likes this";    case 1:      return names[0] + " likes this";    case 2:      return names[0] + " and " + names[1] + " like this";    case 3:      return names[0] + ", " + names[1] + " and " + names[2] + " like this";    default:       return names[0] + ", " + names[1] + " and " + (names.length-2) + " others like this";  }}

????后序

本系列会定期更新的,题目会由浅到深的逐步提高。

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