背景
- 有两个服务,A服务有一个文件上传的接口,B服务通过restTemplate调用A服务的接口上传一个文件。
- B服务曾经拿到文件内容。那么是否可能在不须要生成临时文件的状况下上传文件到A服务呢?
实现过程
定义内容
String fileStr = "文件内容";
字符串转换成byte[]
byte[] xmlBytes = fileStr.getBytes();
自定义MultipartFile实现类
public class BASE64DecodedMultipartFile implements MultipartFile { // 上传文件字节流 private final byte[] imgContent; // 上传文件的文件名 private final String originalFilename; public BASE64DecodedMultipartFile(byte[] imgContent, String originalFilename) { this.imgContent = imgContent; this.originalFilename = originalFilename; } @Override public String getName() { // TODO - implementation depends on your requirements return null; } @Override public String getOriginalFilename() { // TODO - implementation depends on your requirements return this.originalFilename; } @Override public String getContentType() { // TODO - implementation depends on your requirements return null; } @Override public boolean isEmpty() { return imgContent == null || imgContent.length == 0; } @Override public long getSize() { return imgContent.length; } @Override public byte[] getBytes() throws IOException { return imgContent; } @Override public InputStream getInputStream() throws IOException { return new ByteArrayInputStream(imgContent); } @Override public void transferTo(File dest) throws IOException, IllegalStateException { new FileOutputStream(dest).write(imgContent); }}
结构上传文件对象
MultipartFile mf = new BASE64DecodedMultipartFile(xmlBytes, fileName);
通过restTemplate调用近程接口
HttpHeaders headers = new HttpHeaders();headers.setContentType(MediaType.MULTIPART_FORM_DATA);MultiValueMap<String, Object> requestparams = new LinkedMultiValueMap<>();requestparams.add("file", mf.getResource());requestparams.add("filename", mf.getOriginalFilename());HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<>(requestparams, headers);Object resultVo = restTemplate.postForObject(url, requestEntity, Object.class);