话说有一文章表article，存储文章的增加文章的工夫是add_time字段，该字段为int(5)类型的，现须要查问明天增加的文章总数并且依照工夫从大到小排序，则查问语句如下： 02     03    1    select * from `article` where date_format(from_UNIXTIME(`add_time`),'%Y-%m-%d') = date_format(now(),'%Y-%m-%d'); 04 或者： 05     06    1    select * from `article` where to_days(date_format(from_UNIXTIME(`add_time`),'%Y-%m-%d')) = to_days(now()); 07 假如以上表的add_time字段的存储类型是DATETIME类型或者TIMESTAMP类型，则查问语句也可按如下写法： 08     09 查问明天的信息记录： 10     11    1    select * from `article` where to_days(`add_time`) = to_days(now()); 12 查问昨天的信息记录： 13     14    1    select * from `article` where to_days(now()) – to_days(`add_time`) <= 1; 15 查问近7天的信息记录： 16     17    1    select * from `article` where date_sub(curdate(), INTERVAL 7 DAY) <= date(`add_time`); 18 查问近30天的信息记录： 19     20    1    select * from `article` where date_sub(curdate(), INTERVAL 30 DAY) <= date(`add_time`); 21 查问本月的信息记录： 22     23    1    select * from `article` where date_format(`add_time`, ‘%Y%m') = date_format(curdate() , ‘%Y%m'); 24 查问上一月的信息记录： 25     26    1    select * from `article` where period_diff(date_format(now() , ‘%Y%m') , date_format(`add_time`, ‘%Y%m')) =1; 27 对下面的SQL语句中的几个函数做一下剖析： 28     29    （1）to_days 30     31 就像它的名字一样，它是将具体的某一个日期或工夫字符串转换到某一天所对应的unix工夫戳，如： 32     33    01   mysql> select  to_days('2010-11-22 14:39:51'); 34    02    +--------------------------------+                                                       35    03   | to_days('2010-11-22 14:39:51') |36    04   +--------------------------------+37    05   |                         734463 |38    06   +--------------------------------+39    07   40    08   mysql> select  to_days('2010-11-23 14:39:51'); 41    09   +--------------------------------+42    10   | to_days('2010-11-23 14:39:51') |43    11   +--------------------------------+44    12   |                         734464 |45    13   +--------------------------------+46 能够看出22日与23日的差异就是，转换之后的数减少了1，这个粒度的查问是比拟毛糙的，有时可能不能满足咱们的查问要求，那么就须要应用细粒度的查询方法str_to_date函数了，上面将剖析这个函数的用法。 47     48 揭示： 49     50    （1）to_days() 不用于阳历呈现(1582)前的值，起因是当日历扭转时，遗失的日期不会被思考在内。因而对于1582 年之前的日期(或者在其它地区为下一年 ), 该函数的结果实不牢靠的。 51      52    （2）MySQL"日期和工夫类型"中的规定是将日期中的二位数年份值转化为四位。因而对于'1997-10-07'和'97-10-07'将被视为同样的日期: 53     54    1    mysql> select to_days('1997-10-07'), to_days('97-10-07'); 55    2    56    3    -> 729669, 72966957    （2）str_to_date 58     59 这个函数能够把字符串工夫齐全的翻译过去，如： 60     61    1    mysql> select str_to_date("2010-11-23 14:39:51",'%Y-%m-%d %H:%i:%s'); 62    2    63    3    +--------------------------------------------------------+64    4    | str_to_date("2010-11-23 14:39:51",'%Y-%m-%d %H:%i:%s') |65    5    +--------------------------------------------------------+66    6    | 2010-11-23 14:39:51                                    |67    7    +--------------------------------------------------------+68 具体案例操作如下： 69     70    1    select str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s') 71    2    from article 72    3    where str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s')>='2012-06-28 08:00:00' and str_to_date(article.`add_time`,'%Y-%m-%d %H:%i:%s')<='2012-06-28 09:59:59';[![复制代码](https://common.cnblogs.com/images/copycode.gif)](javascript:void(0); "复制代码")[![复制代码](https://common.cnblogs.com/images/copycode.gif)](javascript:void(0); "复制代码")查问明天 select * from 表名 where to_days(工夫字段名) = to_days(now());  昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 工夫字段名) <= 1 7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(工夫字段名)  近30天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(工夫字段名) 本月 SELECT * FROM 表名 WHERE DATE_FORMAT( 工夫字段名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )  上一月 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 工夫字段名, ‘%Y%m’ ) ) =1 同时，再附上 一个 mysql官网的相干document#查问本季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());#查问上季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));#查问本年数据 select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());#查问上年数据 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year)); 查问以后这周的数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());查问上周的数据SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;查问以后月份的数据 select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')查问间隔以后当初6个月的数据 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();查问上个月的数据 select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where pudate between 上月最初一天and 下月第一天 where   date(regdate)   = curdate(); select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())SELECT date( c_instime ) ,curdate( )FROM `t_score`WHERE 1 LIMIT 0 , 30