明天给大家分享一下一个敌人买的实战我的项目包，这个敌人呢跟大部分在座的一样，大学时就是天天打游戏泡酒吧，技术那是齐全拉垮，虽说校招前恶补了两个月理论知识，但我的项目实战经验为零啊，这就如同某些人恋爱实践一套一套的，但你要问他谈过几个女朋友，他能跟你急眼，别问，问就是处男。强调一下真的是敌人，不是我[doge]。
这种状况下显然是找不到称心的工作的，没辙啊，我这位敌人又只能恶补我的项目实战，网上找了许久，明天跟我说这个看起来还不错，于是先花328买了一个小我的项目包，咱们来看看这个我的项目有哪些货色。
篇幅所限，只给大家贴出局部源码，感兴趣的敌人能够点赞评论【我的项目实战】或者进群973961276即可取得所有源码跟电子书哦！
我的项目实战相干的视频材料我放在这里了☞c/c++ 我的项目实战，学习办法在这里☞企业级我的项目实战，三个月疾速待业！
一、C和指针材料
这个文件夹里次要有一本叫《C和指针》的电子书和一些源码，其余一些系统就不表了，我在上面贴一些电子书的截图和局部源码给大家看看。
《C和指针》☟
《C和指针源代码及答案》☟
rearrang
/*** This program reads input lines from the standard input and prints** each input line, followed by just some portions of the lines, to** the standard output.**** The first input is a list of column numbers, which ends with a** negative number. The column numbers are paired and specify** ranges of columns from the input line that are to be printed.** For example, 0 3 10 12 -1 indicates that only columns 0 through 3** and columns 10 through 12 will be printed.*/#include <stdio.h>#include <stdlib.h>#include <string.h>#define MAX_COLS 20 /* max # of columns to process */#define MAX_INPUT 1000 /* max len of input & output lines */int read_column_numbers( int columns[], int max );void rearrange( char *output, char const *input, int n_columns, int const columns[] );intmain( void ){ int n_columns; /* # of columns to process */ int columns[MAX_COLS]; /* the columns to process */ char input[MAX_INPUT]; /* array for input line */ char output[MAX_INPUT]; /* array for output line */ /* ** Read the list of column numbers */ n_columns = read_column_numbers( columns, MAX_COLS ); /* ** Read, process and print the remaining lines of input. */ while( gets( input ) != NULL ){ printf( "Original input : %sn", input ); rearrange( output, input, n_columns, columns ); printf( "Rearranged line: %sn", output ); } return EXIT_SUCCESS;}/*** Read the list of column numbers, ignoring any beyond the specified** maximum.*/intread_column_numbers( int columns[], int max ){ int num = 0; int ch; /* ** Get the numbers, stopping at eof or when a number is < 0. */ while( num < max && scanf( "%d", &columns[num] ) == 1 && columns[num] >= 0 ) num += 1; /* ** Make sure we have an even number of inputs, as they are ** supposed to be paired. */ if( num % 2 != 0 ){ puts( "Last column number is not paired." ); exit( EXIT_FAILURE ); } /* ** Discard the rest of the line that contained the final ** number. */ while( (ch = getchar()) != EOF && ch != 'n' ) ; return num;}/*** Process a line of input by concatenating the characters from** the indicated columns. The output line is then NUL terminated.*/voidrearrange( char *output, char const *input, int n_columns, int const columns[] ){ int col; /* subscript for columns array */ int output_col; /* output column counter */ int len; /* length of input line */ len = strlen( input ); output_col = 0; /* ** Process each pair of column numbers. */ for( col = 0; col < n_columns; col += 2 ){ int nchars = columns[col + 1] - columns[col] + 1; /* ** If the input line isn't this long or the output ** array is full, we're done. */ if( columns[col] >= len || output_col == MAX_INPUT - 1 ) break; /* ** If there isn't room in the output array, only copy ** what will fit. */ if( output_col + nchars > MAX_INPUT - 1 ) nchars = MAX_INPUT - output_col - 1; /* ** Copy the relevant data. */ strncpy( output + output_col, input + columns[col], nchars ); output_col += nchars; } output[output_col] = '0';} s_srch1
/*** Given a pointer to a NULL-terminated list of pointers, search** the strings in the list for a particular character.*/#include <stdio.h>#define TRUE 1#define FALSE 0intfind_char( char **strings, char value ){ char *string; /* the string we're looking at */ /* ** For each string in the list ... */ while( ( string = *strings++ ) != NULL ){ /* ** Look at each character in the string to see if ** it is the one we want. */ while( *string != '0' ){ if( *string++ == value ) return TRUE; } } return FALSE;} 二、WEB外挂
这个文件夹外面同样是有《外挂制作教程》和配套的电子书。一起来看看
外挂制作教程☟
《网络游戏外挂》☟
三、Windows程序设计
Windows程序开发指南☟
code☟
四、数据结构
大略就是这些货色了，剩下的几个我的项目和配套电子书如果有人看的话再更新一下吧，点个赞让我晓得有人在看好吗