问题
接口胜利后返回 form 等一堆码
但不跳转
<form name="punchout_form" method="post" action="https://openapi.alipay.com/gateway.do?app_cert_sn=78b35e11ea21431114619365ac443f29&charset=UTF-8&alipay_root_cert_sn=687b59193f3f462dd5336e5abf83c5d8_02941eef3187dddf3d3b83462e1dfcf6&method=alipay.trade.page.pay&sign=UGxkPWF5w0hhMI0cUu%2BZPJZE3LCs%%2B81WCeM1P6mOqeXwToIqeL4NP1Gm6%2FzP%%2Fq3gtve%2BLJhvUpdgtZHOlvPPnohecyRiD5touIdee7%2BRgk6N35Zb53J3RTMLuWEml%3D%3D&return_url=http%3A%2F%2Fwww.yinongpuhui.com&notify_url=https%3A%2F%2Fwww.yinongpuhui.com%3A8000%2Forder%2FaliPayCallback&version=1.0&app_id=2021001129646221&sign_type=RSA2&timestamp=2020-09-16+15%3A24%3A53&alipay_sdk=alipay-sdk-java-4.8.73.ALL&format=json"> <input type="hidden" name="biz_content" value="{&quot;out_trade_no&quot;:&quot;20200916152453160733&quot;,&quot;total_amount&quot;:&quot;80.00&quot;,&quot;subject&quot;:&quot;product_code&quot;:&quot;FAST_INSTANT_TRADE_PAY&quot;}"> <input type="submit" value="立刻领取"  ></form>
解决

页面中加一个divform标签 （以下代码放在接口胜利的地位）

//支付宝领取 // 增加之前先删除一下，如果单页面，页面不刷新，增加进去的内容会始终保留在页面中，二次调用form表单会出错 let divForm = document.getElementsByTagName('divform')    if (divForm.length) {        console.log('divForm.length')        /*document.body.removeChild(divForm[0])*/        document.getElementsByTagName.innerHTML = ""; // 不革除会出错 } const div=document.createElement('divform'); div.innerHTML=response; // data就是接口返回的form 表单字符串 document.body.appendChild(div); document.forms[0].setAttribute('target', '_blank') // 新开窗口跳转 document.forms[0].submit();/*