向量使咱们能够在单个数据结构中存储多个值,该构造将所有值彼此相邻搁置在内存中。 向量只能存储雷同类型的值。当咱们具备我的项目列表时,例如文件中的文本行或购物车中我的项目的价格时,它们很有用。
新建一个vector
fn main() { let v: Vec<i32> = Vec::new(); println!("{:?}", v)}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn) Finished dev [unoptimized + debuginfo] target(s) in 1.06s Running `target\debug\cargo_learn.exe`[]
能够看到其实vector就是一个数组,只不过有一个要求就是数组中的每一个元素必须具备雷同的类型,上面创立一个实在的实例:
fn main() { let v = vec![1, 2, 3]; println!("{:?}", v);}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn) Finished dev [unoptimized + debuginfo] target(s) in 0.52s Running `target\debug\cargo_learn.exe`[1, 2, 3]
如果不必雷同类型的数据会怎么呢?
fn main() { let v = vec![1, 2.1, 3]; println!("{:?}", v);}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn)error[E0308]: mismatched types --> src\main.rs:2:21 |2 | let v = vec![1, 2.1, 3]; | ^^^ expected integer, found floating-point numbererror: aborting due to previous errorFor more information about this error, try `rustc --explain E0308`.error: could not compile `cargo_learn`.To learn more, run the command again with --verbose.
更新一个向量
在rust中不论更新任何变量,其必须是可变的
fn main() { let mut v = Vec::new(); v.push(5); v.push(6); v.push(7); v.push(8); println!("{:?}", v)}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn) Finished dev [unoptimized + debuginfo] target(s) in 0.57s Running `target\debug\cargo_learn.exe`[5, 6, 7, 8]
能够看出跟js中的数组没有任何区别,至多在应用push办法上~~
删除一个向量
与rust中的一般变量一样,向量也是一个变量,在超出其作用域之后会被主动清理,例如:
fn main() { { let v = vec![1, 2, 3, 4]; // 在此能够用v做任何想做且能做的事件 } // <- v超出范围并在此处开释}
读取向量中的元素
有两种形式获取向量中的元素:应用索引和应用get办法:
fn main() { let v = vec![1, 2, 3, 4, 5]; let third: &i32 = &v[2]; println!("第三个元素是: {}", third); match v.get(2) { Some(third) => println!("第三个元素是: {}", third), None => println!("第三个元素不存在"), }}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn) Finished dev [unoptimized + debuginfo] target(s) in 0.52s Running `target\debug\cargo_learn.exe`第三个元素是: 3第三个元素是: 3
间接应用索引值的话,如果索引值超出了向量的长度范畴(0 ~ 长度-1),会导致编译或者运行出错,应用get办法能够平安的获取元素与捕捉异样。
应用get办法能够简略一点,比方:
let does_not_exist = v.get(100); println!("{:?}", does_not_exist);
此时,如果索引超出了向量能够被索引的范畴的话会返回None
有意思的是如果略微不留神仍旧会碰到所有权的景象:
fn main() { let mut v = vec![1, 2, 3, 4, 5]; let first = &v[0]; v.push(6); println!("The first element is: {}", first);}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn)error[E0502]: cannot borrow `v` as mutable because it is also borrowed as immutable --> src\main.rs:6:5 |4 | let first = &v[0]; | - immutable borrow occurs here5 | 6 | v.push(6); | ^^^^^^^^^ mutable borrow occurs here7 | 8 | println!("The first element is: {}", first); | ----- immutable borrow later used hereerror: aborting due to previous errorFor more information about this error, try `rustc --explain E0502`.error: could not compile `cargo_learn`.To learn more, run the command again with --verbose.
遍历向量中的值
1、一般遍历,并打印出向量中的所有值
fn main() { let v = vec![100, 32, 57]; for i in &v { println!("{}", i); }}
2、遍历并依照肯定规定扭转向量中的值
fn main() { let mut v = vec![100, 32, 57]; for i in &mut v { *i += 50; }}
要更改可变援用所援用的值,必须先应用解援用运算符(*)来获取i中的值,而后能力应用+ =运算符。
应用枚举存储多种类型
在rust中枚举的变体是在雷同的枚举类型下定义的,因而当咱们须要在向量中存储不同类型的元素时,咱们能够定义和应用枚举!例如:
fn main() { #[derive(Debug)] enum SpreadsheetCell { Int(i32), Float(f64), Text(String), } let row = vec![ SpreadsheetCell::Int(3), SpreadsheetCell::Text(String::from("blue")), SpreadsheetCell::Float(10.12), ]; println!("{:?}", row)}D:\learn\cargo_learn>cargo run Compiling cargo_learn v0.1.0 (D:\learn\cargo_learn) Finished dev [unoptimized + debuginfo] target(s) in 0.63s Running `target\debug\cargo_learn.exe`[Int(3), Text("blue"), Float(10.12)]
也能够了解为使其可行的起因是:将枚举当做了一种类型存储在向量中