antd-Table-上移下移问题

[状态管理 mobx](https://cn.mobx.js.org/)import { observable ,action, toJS } from 'mobx';@observable DataSource = []; // 表格列表数据@observable selectedObj = {}; // 选中的数据@observable selectedRowKey = ''; // 当前行index// 上移@action MoveUp(){ // 下面三行代码意思就相当于冒泡排序 替换ordernum这个值      let x = this.selectedRowKey      let orderNum = this.DataSource[x- 1].orderNum; // 点击当前行index的上一条数据(根据index获取数据)      this.DataSource[x - 1].orderNum = this.DataSource[x].orderNum; // 上移的orderNum 等于 当前点击数据的orderNum      this.DataSource[x].orderNum = orderNum; // 当前数据的orderNum 等于上移orderNum      this.selectedObj.orderNum = orderNum;      // 使用splice来交换数据      this.DataSource        .splice(x- 1, 1, ...this.DataSource          .splice((x+ 1) - 1, 1, this.DataSource[x - 1]));}// 下移@action moveDown(){      // 同理上移      let x = this.selectedRowKey + 1;      let y = this.selectedRowKey + 2;      let a = this.selectedRowKey;      let orderNum = this.DataSource[a + 1].orderNum;       this.DataSource[a + 1].orderNum = this.DataSource[a].orderNum;       this.DataSource[a].orderNum = orderNum;       this.selectedObj.orderNum = orderNum;      this.DataSource        .splice(x - 1, 1, ...this.DataSource          .splice(y - 1, 1, this.DataSource[x - 1]))}