刷题继续
昨天和大家分享了71-80题，今天继续来刷81~90题
Question 81:
By using list comprehension, please write a program to print the list after removing numbers which are divisible by 5 and 7 in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]li = [x for x in li if x % 35!=0]print(li)Question 82:
By using list comprehension, please write a program to print the list after removing the 0th, 2nd, 4th,6th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]li = [li[i] for i in range(len(li)) if i%2 != 0]print(li)解法二
li = [12,24,35,70,88,120,155] li = [x for (i,x) in enumerate(li) if i%2!=0]print(li)Question 83:
By using list comprehension, please write a program to print the list after removing the 2nd - 4th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]li = [x for (i,x) in enumerate(li) if i<3 or 4<i]print(li)Question 84:
By using list comprehension, please write a program generate a 3*5*8 3D array whose each element is 0.
解法一
array = [[ [0 for col in range(8)] for col in range(5)] for row in range(3)]print(array)Question 85:
By using list comprehension, please write a program to print the list after removing the 0th,4th,5th numbers in [12,24,35,70,88,120,155].
解法一
li = [12,24,35,70,88,120,155]li = [li[i] for i in range(len(li)) if i not in (0,4,5)]print(li)Question 86:
By using list comprehension, please write a program to print the list after removing the value 24 in [12,24,35,24,88,120,155].
解法一
li = [12,24,35,24,88,120,155]li.remove(24) # this will remove only the first occurrence of 24print(li)解法二
li = [12,24,35,24,88,120,155]li = [x for x in li if x!=24] # Delete all 24print(li)Question 87:
With two given lists [1,3,6,78,35,55] and [12,24,35,24,88,120,155], write a program to make a list whose elements are intersection of the above given lists.
解法一
set1=set([1,3,6,78,35,55])set2=set([12,24,35,24,88,120,155])result = set1.intersection(set2)print(result)解法二
set1=set([1,3,6,78,35,55])set2=set([12,24,35,24,88,120,155])result = set1 & set2print(result)Question 88:
With a given list [12,24,35,24,88,120,155,88,120,155], write a program to print this list after removing all duplicate values with original order reserved.
解法一
li=[12,24,35,24,88,120,155,88,120,155] result = set(li) #> Python 3.6 Set keep the order testprint(result) 解法二
def removeDuplicate( li ): seen = {} for item in li: if item not in seen: seen[item] = True yield itemli = [12, 24, 35, 24, 88, 120, 155, 88, 120, 155]ans = list(removeDuplicate(li))print(ans)解法三
li = [12,24,35,24,88,120,155,88,120,155]for i in li: if li.count(i) > 1: li.remove(i)print(li)Question 89:
Define a class Person and its two child classes: Male and Female. All classes have a method "getGender" which can print "Male" for Male class and "Female" for Female class.
解法一
class Person(object): def getGender( self ): return "Unknown" class Male( Person ): def getGender( self ): return "Male" class Female( Person ): def getGender( self ): return "Female" # TestaMale = Male() aFemale= Female() print(aMale.getGender()) print (aFemale.getGender())Question 90:
Please write a program which count and print the numbers of each character in a string input by console.*Example:
If the following string is given as input to the program:*
abcdefgabcThen, the output of the program should be:
a,2c,2b,2e,1d,1g,1f,1解法一
s=input()dic = {word:s.count(word) for word in s}for k, v in dic.items(): print(f"{k},{v}")解法二
s = input()for letter in range(ord('a'),ord('z')+1): # ord() gets the ascii value of a char letter = chr(letter) # chr() gets the char of an ascii value cnt = s.count(letter) if cnt > 0: print("{},{}".format(letter,cnt))源代码下载
这十道题的代码在我的github上，如果大家想看一下每道题的输出结果，可以点击以下链接下载：
- Python 81-90题
我的运行环境Python 3.6+,如果你用的是Python 2.7版本，绝大多数不同就体现在以下3点：
- raw_input()在Python3中是input()
- print需要加括号
- fstring可以换成.format(),或者%s，%d
谢谢大家，我们下期见！希望各位朋友不要吝啬，把每道题的更高效的解法写在评论里，我们一起进步！！！