刷题继续
上一期和大家分享了前10道题，今天继续来刷11~20
Question 11:
Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a comma separated sequence.Example:
0100,0011,1010,1001Then the output should be:
1010Notes: Assume the data is input by console.
解法一
def check(x): # check function returns true if divisible by 5 return int(x,2)%5 == 0 # int(x,b) takes x as string and b as base from which # it will be converted to decimaldata = input().split(',')data = list(filter(check,data)) # in filter(func,object) function, elements are picked from 'data' if found True by 'check' functionprint(",".join(data))解法二
value = []items=[int(x) for x in input().split(',')]result = " ".join(str(x) for x in items if x %5==0 )print(",".join(result))解法三
data = input().split(',')data = list(filter(lambda i:int(i,2)%5==0,data)) print(",".join(data))Question 12:
Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number.The numbers obtained should be printed in a comma-separated sequence on a single line.
解法一
values = []for i in range(1000, 3001): s = str(i) if (int(s[0])%2==0) and (int(s[1])%2==0) and (int(s[2])%2==0) and (int(s[3])%2==0): values.append(s)print (",".join(values))解法二
lst = []for i in range(1000,3001): flag = 1 for j in str(i): # every integer number i is converted into string if ord(j)%2 != 0: # ord returns ASCII value and j is every digit of i flag = 0 # flag becomes zero if any odd digit found if flag == 1: lst.append(str(i)) # i is stored in list as stringprint(",".join(lst)) 解法三
def check(element): return all(ord(i)%2 == 0 for i in element) # all returns True if all digits i is even in elementlst = [str(i) for i in range(1000,3001)] # creates list of all given numbers with string data typelst = list(filter(check,lst)) # filter removes element from list if check condition failsprint(",".join(lst))解法四
lst = [str(i) for i in range(1000,3001)]lst = list(filter(lambda i:all(ord(j)%2 == 0 for j in i),lst )) # using lambda to define function inside filter functionprint(",".join(lst))Question 13:
Write a program that accepts a sentence and calculate the number of letters and digits.Suppose the following input is supplied to the program:
hello world! 123Then, the output should be:
LETTERS 10DIGITS 3解法一
text_input = input()d={"DIGITS":0, "LETTERS":0,'SPACE':0}d['DIGITS']= sum(c.isdigit() for c in text_input)d['LETTERS']= sum(c.isalpha() for c in text_input)d['SPACE'] = sum(c.isspace() for c in text_input)for k,v in d.items(): print(k,v)解法二
word = input()letter,digit = 0,0for i in word: if ('a'<=i and i<='z') or ('A'<=i and i<='Z'): letter+=1 if '0'<=i and i<='9': digit+=1print("LETTERS {0}\nDIGITS {1}".format(letter,digit))解法三
word = input()letter,digit = 0,0for i in word: letter+=i.isalpha() # returns True if alphabet digit+=i.isnumeric() # returns True if numericprint("LETTERS %d\nDIGITS %d"%(letter,digit)) # two different types of formating method is shown in both solutionQuestion 14:
Write a program that accepts a sentence and calculate the number of upper case letters and lower case letters.Suppose the following input is supplied to the program:
Hello world!Then, the output should be:
UPPER CASE 1LOWER CASE 9解法一
word = input()upper,lower = 0,0for i in word: if 'a'<=i and i<='z' : lower+=1 if 'A'<=i and i<='Z': upper+=1print("UPPER CASE {0}\nLOWER CASE {1}".format(upper,lower))解法二
text_input = input()d={"UPPER CASE":0, "LOWER CASE":0}for c in text_input: if c.isupper(): d["UPPER CASE"]+=1 elif c.islower(): d["LOWER CASE"]+=1 else: passprint ("UPPER CASE", d["UPPER CASE"])print ("LOWER CASE", d["LOWER CASE"])解法三
word = input()upper = sum(1 for i in word if i.isupper()) lower = sum(1 for i in word if i.islower())print("UPPER CASE {0}\nLOWER CASE {1}".format(upper,lower))Question 15:
Write a program that computes the value of a+aa+aaa+aaaa with a given digit as the value of a.Suppose the following input is supplied to the program:
9Then, the output should be:
11106解法一
a = input()total,tmp = 0,str() # initialing an integer and empty stringfor i in range(4): tmp+=a # concatenating 'a' to 'tmp' total+=int(tmp) # converting string type to integer typeprint(total)解法二
a = input()total = int(a) + int(2*a) + int(3*a) + int(4*a) # N*a=Na, for example a="23", 2*a="2323",3*a="232323"print(total)Question 16:
Use a list comprehension to square each odd number in a list. The list is input by a sequence of comma-separated numbers.
Suppose the following input is supplied to the program:
1,2,3,4,5,6,7,8,9Then, the output should be:
1,3,5,7,9解法一
values = input()numbers = [x for x in values.split(",") if int(x)%2!=0]print (",".join(numbers))Question 17:
Write a program that computes the net amount of a bank account based a transaction log from console input. The transaction log format is shown as following:
D 100W 200- D means deposit while W means withdrawal.
Suppose the following input is supplied to the program:
D 300D 300W 200D 100Then, the output should be:
500解法一
netAmount = 0while True: s = input() if not s: break values = s.split(" ") operation = values[0] amount = int(values[1]) if operation=="D": netAmount+=amount elif operation=="W": netAmount-=amount else: passprint(netAmount)解法二
total = 0while True: s = input().split() if not s: # break if the string is empty break cm,num = map(str,s) if cm=='D': total+=int(num) if cm=='W': total-=int(num)print(total)Question 18:
A website requires the users to input username and password to register. Write a program to check the validity of password input by users.Following are the criteria for checking the password:
- At least 1 letter between [a-z]
- At least 1 number between [0-9]
- At least 1 letter between [A-Z]
- At least 1 character from [$#@]
- Minimum length of transaction password: 6
- Maximum length of transaction password: 12
Your program should accept a sequence of comma separated passwords and will check them according to the above criteria. Passwords that match the criteria are to be printed, each separated by a comma.Example
If the following passwords are given as input to the program:
ABd1234@1,a F1#,2w3E*,2We3345Then, the output of the program should be:
ABd1234@1解法一
import revalue = []items=[x for x in input().split(',')]for p in items: if (len(p)<6 or len(p)>12): break elif not re.search("[a-z]",p): break elif not re.search("[0-9]",p): break elif not re.search("[A-Z]",p): break elif not re.search("[$#@]",p): break elif re.search("\s",p): break else: value.append(p) breakprint (",".join(value))解法二
def is_low(x): # Returns True if the string has a lowercase for i in x: if 'a'<=i and i<='z': return True return Falsedef is_up(x): # Returns True if the string has a uppercase for i in x: if 'A'<= i and i<='Z': return True return Falsedef is_num(x): # Returns True if the string has a numeric digit for i in x: if '0'<=i and i<='9': return True return Falsedef is_other(x): # Returns True if the string has any "$#@" for i in x: if i=='$' or i=='#' or i=='@': return True return Falses = input().split(',') lst = []for i in s: length = len(i) if 6 <= length and length <= 12 and is_low(i) and is_up(i) and is_num(i) and is_other(i): #Checks if all the requirments are fulfilled lst.append(i)print(",".join(lst))解法三
def check(x): cnt = (6<=len(x) and len(x)<=12) for i in x: if i.isupper(): cnt+=1 break for i in x: if i.islower(): cnt+=1 break for i in x: if i.isnumeric(): cnt+=1 break for i in x: if i=='@' or i=='#'or i=='$': cnt+=1 break return cnt == 5 # counting if total 5 all conditions are fulfilled then returns Trues = input().split(',')lst = filter(check,s) # Filter function pick the words from s, those returns True by check() functionprint(",".join(lst))解法四
import res = input().split(',')lst = []for i in s: cnt = 0 cnt+=(6<=len(i) and len(i)<=12) cnt+=bool(re.search("[a-z]",i)) # here re module includes a function re.search() which returns the object information cnt+=bool(re.search("[A-Z]",i)) # of where the pattern string i is matched with any of the [a-z]/[A-z]/[0=9]/[@#$] characters cnt+=bool(re.search("[0-9]",i)) # if not a single match found then returns NONE which converts to False in boolean cnt+=bool(re.search("[@#$]",i)) # expression otherwise True if found any. if cnt == 5: lst.append(i)print(",".join(lst))Question 19:
You are required to write a program to sort the (name, age, score) tuples by ascending order where name is string, age and score are numbers. The tuples are input by console. The sort criteria is:
- 1: Sort based on name
- 2: Then sort based on age
- 3: Then sort by score
The priority is that name > age > score.If the following tuples are given as input to the program:
Tom,19,80John,20,90Jony,17,91Jony,17,93Json,21,85Then, the output of the program should be:
[('John', '20', '90'), ('Jony', '17', '91'), ('Jony', '17', '93'), ('Json', '21', '85'), ('Tom', '19', '80')]解法一
lst = []while True: s = input().split(',') if not s[0]: # breaks for blank input break lst.append(tuple(s))lst.sort(key= lambda x:(x[0],x[1],x[2])) print(lst)Question 20:
Define a class with a generator which can iterate the numbers, which are divisible by 7, between a given range 0 and n.
解法一
class Test: def generator(self,n): return [i for i in range(n) if i%7==0] n = int(input())num = Test()lst = num.generator(n)print(lst)源代码下载
这十道题的代码在我的github上，如果大家想看一下每道题的输出结果，可以点击以下链接下载：
- Python 11-20题
我的运行环境Python 3.6+,如果你用的是Python 2.7版本，绝大多数不同就体现在以下3点：
- raw_input()在Python3中是input()
- print需要加括号
- fstring可以换成.format(),或者%s，%d
谢谢大家，我们下期见！希望各位朋友不要吝啬，把每道题的更高效的解法写在评论里，我们一起进步！！！