通过查看源码可得知:1. 前言抽象类中AbstractUserDetailsAuthenticationProvider 接口抛出异常AuthenticationException下面源码注释这么描述 * * @throws AuthenticationException if the credentials could not be validated * (generally a <code>BadCredentialsException</code>, an * <code>AuthenticationServiceException</code> or * <code>UsernameNotFoundException</code>) */ protected abstract UserDetails retrieveUser(String username, UsernamePasswordAuthenticationToken authentication) throws AuthenticationException;AuthenticationException 抛出的情况是 BadCredentialsException,AuthenticationServiceException,UsernameNotFoundException这三个异常。当UserNameNotFoundException 这个异常的情况下会抛出可实际情况下我们 查询的user为null 抛出了 UserNameNotFoundException 这个异常但是实际并没有抛出来,抛出的是 AuthenticationException 通过继续往下查看源码后明白了,原来是做了对UserNameNotFoundException 处理,转换成了AuthenticationException 这个异常;hideUserNotFoundExceptions = true;…boolean cacheWasUsed = true; UserDetails user = this.userCache.getUserFromCache(username); if (user == null) { cacheWasUsed = false; try { user = retrieveUser(username, (UsernamePasswordAuthenticationToken) authentication); } catch (UsernameNotFoundException notFound) { logger.debug(“User ‘” + username + “’ not found”); if (hideUserNotFoundExceptions) { throw new BadCredentialsException(messages.getMessage( “AbstractUserDetailsAuthenticationProvider.badCredentials”, “Bad credentials”)); } else { throw notFound; } }所以我们没有抛出UsernameNotFoundException 这个异常,而是将这个异常进行了转换。2.解决办法如何抛出这个异常,那就是将hideUserNotFoundExceptions 设置为 false;2.1设置实现类中 @Bean public DaoAuthenticationProvider authenticationProvider() { DaoAuthenticationProvider provider = new DaoAuthenticationProvider(); provider.setHideUserNotFoundExceptions(false); provider.setUserDetailsService(mUserDetailsService); provider.setPasswordEncoder(passwordEncoder); return provider; }最后在WebSecurityConfig配置即可 auth.authenticationProvider(daoAuthenticationProvider());2.2 debug来看一下设置之前设置之后抛出的UsernameNotFoundException 异常已经捕获到了,然后进入if中最后抛出new BadCredentialsException(messages.getMessage( “AbstractUserDetailsAuthenticationProvider.badCredentials”, “Bad credentials”))会将异常信息存入session中 , 根据key即可获取最后在失败的处理器中获取到@Componentpublic class MyAuthenctiationFailureHandler extends SimpleUrlAuthenticationFailureHandler { public MyAuthenctiationFailureHandler() { this.setDefaultFailureUrl("/loginPage"); } @Override public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, AuthenticationException exception) throws IOException, ServletException { logger.info(“进入认证失败处理类”); HttpSession session = request.getSession(); AuthenticationException attributes = (AuthenticationException) session.getAttribute(“SPRING_SECURITY_LAST_EXCEPTION”); logger.info(“aaaa " + attributes); super.onAuthenticationFailure(request, response, exception); }}这样子做可以直接在session中获取到,如果自定义抛出一个异常首先控制台会报异常错,其次前台的通过如ajax获取错误信息,又得写ajax。这样子做直接将信息存入session中,springSecurity直接为我们封装到session中了,可以直接根据key获取到。如: ${session.SPRING_SECURITY_LAST_EXCEPTION.message}2.4 判断密码注意 如果用户名不存在,抛了异常不要再在密码验证其中抛出密码错误异常,不然抛出UserNameNotFoundException 后还会验证密码是否正确,如果密码正确还好,返回true,如果不正确抛出异常。此时会将 UsernameNotFoundException 异常覆盖,这里应该返回false。源码如下:protected final UserDetails retrieveUser(String username, UsernamePasswordAuthenticationToken authentication) throws AuthenticationException { prepareTimingAttackProtection(); try { UserDetails loadedUser = this.getUserDetailsService().loadUserByUsername(username); if (loadedUser == null) { throw new InternalAuthenticationServiceException( “UserDetailsService returned null, which is an interface contract violation”); } return loadedUser; } catch (UsernameNotFoundException ex) { // 、、、、、、、 这里会去匹配密码是否正确 mitigateAgainstTimingAttack(authentication); throw ex; } catch (InternalAuthenticationServiceException ex) { throw ex; } catch (Exception ex) { throw new InternalAuthenticationServiceException(ex.getMessage(), ex); } }mitigateAgainstTimingAttack 方法 private void mitigateAgainstTimingAttack(UsernamePasswordAuthenticationToken authentication) { if (authentication.getCredentials() != null) { String presentedPassword = authentication.getCredentials().toString(); //这里会是自定义密码加密 this.passwordEncoder.matches(presentedPassword, this.userNotFoundEncodedPassword); } }我的密码加密器 @Override public boolean matches(CharSequence charSequence, String s) { String pwd = charSequence.toString(); log.info(“前端传过来密码为: " + pwd); log.info(“加密后密码为: " + MD5Util.encode(charSequence.toString())); log.info(“数据库存储的密码: " + s); //s 应在数据库中加密 if( MD5Util.encode(charSequence.toString()).equals(MD5Util.encode(s))){ return true; } //throw new DisabledException(”–密码错误–”); //不能抛出异常 return false; }如下是 我们密码验证器里抛出异常后获取到的异常异常密码未验证 之前捕获到的异常信息验证密码后捕获到的异常 (这里跳到ProviderManager中)既然我用户名不对我就不必要验证密码了,所以不应该抛出异常,应该直接返回false。不然。此处密码异常会将 用户不存在进行覆盖!3. 验证页面代码<body>登录页面<div th:text="${session.SPRING_SECURITY_LAST_EXCEPTION!=null?session.SPRING_SECURITY_LAST_EXCEPTION.message:’’}">[…]</div><form method=“post” action="/login” > <input type=“text” name=“username” /><br> <input type=“password” name=“password” /> <input type=“submit” value=“login” /></form>