python 实现私钥加密公钥解密业界普遍的用法是公钥用来加密，私钥来解密，许多人却不知道也可以用私钥加密，公钥来解密基础知识对称加密非对称加密公私钥的几个常见格式图片来源： https://www.openssl.org/docs/…使用私钥加密待编辑使用公钥解密参考文档：https://www.cnblogs.com/masak…https://www.linuxidc.com/Linu...from rsa import PublicKey, common, transform, core# 公钥格式如下，若公钥已经是 RSAPublicKey 格式，则无需将 pub key 转换为 stringPUB_KEY_STRING = ‘MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCsKfRext58G0buLDabQQNBVWEB1/B62PapiZ2tSiITw/3X4cI00QB6m7dryMqs7pKntUD3MTGeMCj9zwXX0kmqkrA8og0H0eOHQnAeuw671lkSVYnD1YVcICPv+fbJ1JL+DP3RkXuy0+V2iQC2GDQmfgTcKVowU4c+ToQIp0pUBQIDAQAB’class DecryptByPublicKey(object): """ 使用 publib key来解密用primary key加密后生成的base64类型的密文 返回解密后的数据 """ def init(self, encrypt_text): self.encrypt_text = encrypt_text @staticmethod def str2key(s): # 对字符串解码, 解码成功返回 模数和指数 b_str = base64.b64decode(s) if len(b_str) < 162: return False hex_str = ’’ # 按位转换成16进制 for x in b_str: h = hex(ord(x))[2:] h = h.rjust(2, ‘0’) hex_str += h # 找到模数和指数的开头结束位置 m_start = 29 * 2 e_start = 159 * 2 m_len = 128 * 2 e_len = 3 * 2 modulus = hex_str[m_start:m_start + m_len] exponent = hex_str[e_start:e_start + e_len] return modulus,exponent @staticmethod def f(cipher, PUBLIC_KEY): """ decrypt msg by public key """ public_key = PublicKey.load_pkcs1(PUBLIC_KEY) encrypted = transform.bytes2int(cipher) decrypted = core.decrypt_int(encrypted, public_key.e, public_key.n) text = transform.int2bytes(decrypted) if len(text) > 0 and text[0] == ‘\x01’: pos = text.find(’\x00’) if pos > 0: return text[pos+1:] else: return None def pub_decrypt_with_pubkeystr(self): """ 将 base64 编码的 pub_key 转成 bio 对象, 再将bio对象转换成公钥对象 """ # 将 pub key 转换为 string # Note: 若公钥已经是 RSAPublicKey 格式，则无需执行这一步 ！ try: key = self.str2key(PUB_KEY_STRING) # 将 base64 编码的公钥进行拆解，取出模数和指数 if not key: raise Exception, “decode public key falid” modulus = int(key[0], 16) exponent = int(key[1], 16) rsa_pubkey = PublicKey(modulus, exponent) # 根据模数和指数生成 pubkey 对象 self.pub_key = rsa_pubkey.save_pkcs1() # 将 pubkey 对象导出为 RSAPublicKey 格式的公钥 except Exception, e: assert False, “Invalid public_key” # 开始解密 try: ret = self.f(self.encrypt_text.decode(“base64”), self.pub_key) except Exception, e: self.error_info = str(e) assert False, “Decrypt by public key fails! Invalid encrypt_text” return retif name == “main”: encrypt_text = ‘xxxxxx’ # encrypt_text 是被私钥加密后的密文 decrypt = DecryptByPublicKey(encrypt_text) result = decrypt.pub_decrypt_with_pubkeystr() print result