题目In a array A of size 2N, there are N+1 unique elements, and exactly one of these elements is repeated N times.Return the element repeated N times.Example 1:Input: [1,2,3,3]Output: 3Example 2:Input: [2,1,2,5,3,2]Output: 2Example 3:Input: [5,1,5,2,5,3,5,4]Output: 5Note:4 <= A.length <= 100000 <= A[i] < 10000A.length is even题目地址讲解这个题目很简单,只要扫描一遍数组,遇到一个数出现两次,就找到了这个数。Java代码class Solution { public int repeatedNTimes(int[] A) { Map<Integer, Integer> map = new HashMap<>(); for(int x:A){ Integer count = map.get(x); if(count==null){ map.put(x, 1); }else{ return x; } } return 0; }}