【C++】 31_完善的复数类

完善的复数类复数类应该具有的操作运算： +, -, *, /比较： ==, !=赋值： =求模： modulus利用操作符重载统一复数与实数的运算方式统一复数与实数的比较方式Complex operator + (const Complex& c);Complex operator - (const Complex& c);Complex operator * (const Complex& c);Complex operator / (const Complex& c); bool operator == (const Complex& c);bool operator != (const Complex& c); Complex& operator = (const Complex& c);编程实验： 复数类的实现Complex.h#ifndef COMPLEX_H#define _COMPLEX_H_class Complex{private: double a; double b;public: Complex(int a = 0, int b = 0); int getA(); int getB(); int getModulus(); Complex operator + (const Complex& c); Complex operator - (const Complex& c); Complex operator * (const Complex& c); Complex operator / (const Complex& c); bool operator == (const Complex& c); bool operator != (const Complex& c); Complex& operator = (const Complex& c);};#endifComplex.cpp#include “Complex.h”#include <math.h>Complex::Complex(int a, int b){ this->a = a; this->b = b;}int Complex::getA(){ return a;}int Complex::getB(){ return b;}int Complex::getModulus(){ return sqrt(a * a + b * b);}Complex Complex::operator + (const Complex& c){ double na = a + c.a; double nb = b + c.a; Complex ret(na, nb); return ret;}Complex Complex::operator - (const Complex& c){ double na = a - c.a; double nb = b - c.b; Complex ret(na, nb); return ret;}Complex Complex::operator * (const Complex& c){ double na = a * c.a - b * c.b; double nb = a * c.b + b * c.a; Complex ret(na, nb); return ret;}Complex Complex::operator / (const Complex& c){ double nm = c.a * c.a + c.b * c.b; double na = (a * c.a + b * c.b) / nm; double nb = (b * c.a - a * c.b) / nm; Complex ret(na, nb); return ret;}bool Complex::operator == (const Complex& c){ return (a == c.a) && (b == c.b);}bool Complex::operator != (const Complex& c){ return !(*this == c);}// 为了实现循环赋值，将自身引用返回Complex& Complex::operator = (const Complex& c){ // 若意图自己给自己赋值，则跳过 if( this != &c ) { a = c.a; b = c.b; } return *this;}main.cpp#include <stdio.h>#include “Complex.h"int main(){ Complex c1(1, 2); Complex c2(3, 6); Complex c3 = c2 - c1; Complex c4 = c2 + c1; Complex c5 = c2 * c1; Complex c6 = c2 / c1; printf(“c3.a = %d, c3.b = %d\n”, c3.getA(), c3.getB()); printf(“c4.a = %d, c4.b = %d\n”, c4.getA(), c4.getB()); printf(“c5.a = %d, c5.b = %d\n”, c5.getA(), c5.getB()); printf(“c6.a = %d, c6.b = %d\n”, c6.getA(), c6.getB()); Complex c7(1, 2); printf(“c1 == c7 : %d\n”, c1 == c7); printf(“c2 != c7 : %d\n”, c2 != c7); (c3 = c2) = c1; printf(“c1.a = %d, c1.b = %d\n”, c1.getA(), c1.getB()); printf(“c2.a = %d, c2.b = %d\n”, c2.getA(), c2.getB()); printf(“c3.a = %d, c3.b = %d\n”, c3.getA(), c3.getB()); return 0;}输出：c3.a = 2, c3.b = 4c4.a = 4, c4.b = 7c5.a = -9, c5.b = 12c6.a = 3, c6.b = 0c1 == c7 : 1c2 != c7 : 1c1.a = 1, c1.b = 2c2.a = 3, c2.b = 6c3.a = 1, c3.b = 2注意事项C++ 规定赋值操作符（==）只能重载为成员函数操作符重载不能改变原操作符的优先级操作符不能改变操作数的个数操作符不应改变操作符的原有语义小结复数的概念可以通过自定义类实现复数中的运算操作符可以通过操作符重载实现赋值操作符只能通过成员函数实现操作符重载的本质为函数定义以上内容参考狄泰软件学院系列课程，请大家保护原创！