关于php:如何在Php中获得一个Final类的Protected的static成员属性

<?php 
final class ConstantOne {
  static protected $ERRNO_OK;
  static protected function init_ERRNO_OK() {
    return 0;
  }
  static protected function init_ErrorMsg() {
    return array(
      0 => "OK",
    );
  }
}

请答题：

如何获取’0′?

谬误形式1

class test extends ConstantOne{

}
ECHO test::init_ERRNO_OK();

形式1起因：

PHP Fatal error: Class test may not inherit from final class (ConstantOne)

谬误形式2

var_dump(ConstantOne::init_ErrorMsg());

形式2起因：

PHP Fatal error: Uncaught Error: Call to protected method ConstantOne::init_ErrorMsg()

思考

staitc的话，我能够不实例化就能够调用，protected的话，能够实例化本类或者父类调用，然而要害是还有个final润饰。Final润饰的类不能被继承，所以只能本类调用，未实例的类调用static的办法又说是因为protected的。static实质是类的办法，

解决思路

/**
 * Base class for constant Management
 */
abstract class BaseConstant
{
    /**
     * Don't instanciate this class
     */
    protected function __construct() {}

    /**
     * Get a constant value
     * @param string $constant
     * @return mixed
     */
    public static function get($constant)
    {
        if(is_null(static::$$constant))
        {
            // echo sprintf('static::init_%s', $constant);
            static::$$constant = call_user_func(
                    sprintf('static::init_%s', $constant)
                );
        }

        return static::$$constant;
    }
}

final class ConstantTwo extends BaseConstant {
  static protected $ERRNO_OK;
  static protected function init_ERRNO_OK() {
    return 100;
  }
  static protected function init_ErrorMsg() {
    return array(
      100 => "OK",
    );
  }

//以下这也也能够
  public static function outOK (){
      echo static::init_ERRNO_OK();
  }
}

echo ConstantTwo::get('ERRNO_OK');

echo ConstantTwo::outOK();