1. 查问英语分数在 80-90 之间的同学。
SELECT stu_id
FROM exam
WHERE score >=80 AND score <=90
AND sub_id = (SELECT subject_id FROM `subject` WHERE subject_name = '英语')
2. 查问数学分数为 89,90,91 的同学。
SELECT * FROM student WHERE stu_no IN(SELECT stu_id FROM exam WHERE score IN(89,90,91)
AND sub_id = (SELECT subject_id FROM `subject` WHERE subject_name = '数学')
)
3. 查问所有姓李的学生问题。
SELECT * FROM exam WHERE stu_id IN (SELECT stu_no FROM student WHERE stuname LIKE "李 %")
4. 查问数 JAVA>80 并且 HTML 分 >80 的同学的信息。
SELECT stu_id , COUNT(*) FROM exam e , `subject` s
WHERE e.sub_id= s.subject_id AND
((e.score >= 80 AND s.subject_name='JAVA')
OR
(e.score >= 90 AND s.subject_name='HTML')
)
GROUP BY stu_id HAVING COUNT(*) = 2
5. 对数学问题排序后输入。
SELECT s.stu_name,e.score
FROM student s INNER JOIN exam e ON s.student_no=e.stu_id INNER
JOIN `subject` k ON e.sub_id=k.subject_id WHERE `subject_name`='JAVA'
ORDER BY e.score ASC;
6. 对总分排序后输入,而后再按从高到低的程序输入
SELECT s.stu_name , SUM(e.score)
FROM student s INNER JOIN exam e ON s.student_no=e.stu_id
GROUP BY e.stu_id ORDER BY SUM(e.score) ASC;
7. 对姓李的学生数学问题排序输入.
SELECT s.stu_name , e.score
FROM student s INNER JOIN exam e ON s.student_no=e.stu_id
WHERE s.stu_name LIKE '李 %'
AND e.`sub_id`=
(SELECT subject_id FROM `subject` WHERE subject_name='JAVA')
ORDER BY e.`score`;
8. 展现学生所有信息与所属年级信息.
SELECT *
FROM student s INNER JOIN grade g ON s.gradeid=g.gradeid
9. 展现所有学生的考试信息.(包含学生, 考试课程, 问题信息.) 三表内连贯.
SELECT *
FROM student s INNER JOIN exam e ON s.student_no=e.stu_id
INNER JOIN `subject` sub ON e.sub_id=sub.subject_id
INNER JOIN grade g ON s.`gradeid`=g.`gradeid`
10. 统计数学问题大于 90 的学生有多少个?
SELECT COUNT(*)
FROM student s INNER JOIN exam e ON s.student_no=e.stu_id
INNER JOIN `subject` sub ON e.sub_id=sub.subject_id
WHERE e.score>90 AND sub.subject_name='JAVA'