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背景
前段时间实现了一个 call-with-tcp-listener 过程（函数）
(call-with-tcp-listener "127.0.0.1:8088" ( lambda (in) ((display (req-read-string in))
"HTTP/1.1 200 OK\r\n\r\n hello word"
)))如果是简略的返回数据还不存在问题，然而当波及到 io 的时候就会呈现阻塞的状况，最简略的解决方案就是一个申请一个线程，然而这种模型开销比拟大，所以想到了线程池，而后就实现了一个及其简略的版本
实现
应用到了 thread + channel + lambda-lep + apply 这几个过程
首先定义一个线程池
async.lisp
((define thread-qty (* (get-os-cpu-num) 2))
(define thread-count 1)
(define barrier (make-barrier thread-qty))
(define channel (make-channel))
(while (< thread-count thread-qty)
((thread-run (lambda () ((channel-for-each (lambda (task) (( task)
)) channel)
(barrier-wait barrier)
;; (loop ((<- channel)))
)))
(set! thread-count (+ thread-count 1))))
(define go (lambda-lep (task) ((apply (`(-> ,channel ,task)))
)))
(export go)
)如何应用
((import (go) from "./async.lisp")
(go
(lambda ()
(println (current-thread-name) "hello rust-lisp!"))))控制台会输入
thread-1 hello rust-lisp!重构
让咱们在联合 call-with-tcp-listener 过程欠缺一下吧
首先重构一下 call-with-tcp-listener 过程使其承受 out port
main.lisp
((def handler (in out) (
;; 模仿 io 读取期待
(sleep 1)
(println (current-thread-name))
(display (req-read-string in))
(write-string "HTTP/1.1 200 OK\r\n\r\n hello word" out)
))
(call-with-tcp-listener "127.0.0.1:8088" ( lambda (in out) (( handler in out)
))))而后应用 go 过程实现工作提交
main.lisp
((load "./lib.lisp")
(import (go) from "./async.lisp")
(def handler (in out) (
;; 模仿 io 读取期待
(sleep 1)
(println (current-thread-name))
(display (req-read-string in))
(write-string "HTTP/1.1 200 OK\r\n\r\n hello word" out)
))
(call-with-tcp-listener "127.0.0.1:8088" ( lambda (in out) ((go (lambda () (handler in out)))
))))工作提交之后, 上面这段代码会从 channel 中读取到最新提交的 task (过程) 而后执行。
(channel-for-each (lambda (task) ((task)
)) channel)运行后拜访 控制台打印如下
thread1
GET / HTTP/1.0
Host: 127.0.0.1:8088
User-Agent: ApacheBench/2.3
Accept: */*async.lisp 源码
正文完
