要求:顺次执行 fetch1=>fetch2=>fetch3,先执行 fetch1,须要将 fetch1 的后果作为 fetch2 的参数,fetch2 的后果作为 fetch3 的参数。
interface IEvents {[key: string]: Array<Function>
}
class EventListener {
events: IEvents
constructor() {this.events = {}
}
listen(key, fn) {let fns = this.events[key];
if (fns) {fns.push(fn)
} else {this.events[key] = [fn]
}
}
on(key, payload) {const fns = this.events[key]
if (fns && fns.length > 0) {const fn = fns.shift()
fn(payload)
}
}
remove(key, fn) {const fns = this.events[key]
if (!Array.isArray(fns)) return
const index = fns.indexOf(fn)
if (index !== -1) {fns.splice(index, 1)
}
}
}
let listener = new EventListener()
const fetch1 = () => {setTimeout(() => {
const res = {
current: 'fetch1',
next: 'fetch2'
}
console.log(res)
listener.on('fetch2', res)
})
}
const fetch2 = (payload) => {setTimeout(() => {
const res = {
current: payload.next,
next: 'fetch3'
}
console.log(res)
listener.on('fetch3', res)
})
}
const fetch3 = (payload) => {
console.log({
current: payload.next,
next: ''
})
}
listener.listen('fetch2', fetch2)
listener.listen('fetch3', fetch3)
fetch1()