关于javascript:JavaScript处理时间当前时间加减法

先封装个办法：

/**
 * @description: 获取以后工夫和进行推算后的工夫(stime, etime)
 * @param {number} period - 向前推算的工夫(s)
 * @return {*}
 */
handleTimeString(period) {
    let etime, stime, timeString, newStime
    // 以后工夫：格局 YYYY-MM-DD HH:MM:SS
    etime = new Date().toLocaleDateString().replace(/\//g, "-") + "" + new Date().toTimeString().split(" ")[0]
    // 将以后工夫包装成规范工夫
    timeString = new Date(etime)
    // 将以秒 (s) 为单位进行演算后的工夫包装成规范工夫
    stime = new Date(timeString.setTime(timeString.getTime() - period))
    // 演算后的工夫：格局 YYYY-MM-DD HH:MM:SS
    newStime = stime.toLocaleDateString().replace(/\//g, "-") + "" + stime.toTimeString().split(" ")[0]
    // 以对象的模式返回
    return {
        stime: newStime,
        etime: etime,
    }
},

实操：

切换工夫：全副转换成秒

switch (timeLimit) {let timeObj = {}
    case "10min":
       timeObj = this.handleTimeString(10 * 60 * 1000)
       break
    case "30min":
       timeObj = this.handleTimeString(30 * 60 * 1000)
       break
    case "1h":
       timeObj = this.handleTimeString(60 * 60 * 1000)
       break
    case "12h":
       timeObj = this.handleTimeString(12 * 60 * 60 * 1000)
       break
    case "1d":
       timeObj = this.handleTimeString(24 * 60 * 60 * 1000)
       break
    case "3d":
       timeObj = this.handleTimeString(3 * 24 * 60 * 60 * 1000)
       break
}

成果：

Keep foolish, keep hungry.