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async/await 的劣势:能够很好地解决 then 链
对于繁多的 Promise 链其实并不能发现 async/await 的劣势,当须要解决由多个 Promise 组成的 then 链的时候,劣势就能体现进去了,
接下来间接上代码:
/**
* 传入参数 n,示意这个函数执行的工夫(毫秒)* 执行的后果是 n + 200,这个值将用于下一步骤
*/
function takeLongTime(n) {
return new Promise(resolve => {setTimeout(() => resolve(n + 200), n);
});
}
function step1(n) {console.log(`step1 with ${n}`);
return takeLongTime(n);
}
function step2(n) {console.log(`step2 with ${n}`);
return takeLongTime(n);
}
function step3(n) {console.log(`step3 with ${n}`);
return takeLongTime(n);
}
当初用 Promise 形式:
function doIt() {console.time("doIt");
const time1 = 300;
step1(time1)
.then(time2 => step2(time2))
.then(time3 => step3(time3))
.then(result => {console.log(`result is ${result}`);
console.timeEnd("doIt");
});
}
doIt();
// c:vartest>node --harmony_async_await .
// step1 with 300
// step2 with 500
// step3 with 700
// result is 900
// doIt: 1507.251ms
输入后果 result
是 step3()
的参数 700 + 200
= 900
。doIt()
程序执行了三个步骤,一共用了 300 + 500 + 700 = 1500
毫秒,和 console.time()/console.timeEnd()
计算的后果统一。
用 async/await 的形式:
async function doIt() {console.time("doIt");
const time1 = 300;
const time2 = await step1(time1);
const time3 = await step2(time2);
const result = await step3(time3);
console.log(`result is ${result}`);
console.timeEnd("doIt");
}
doIt();
后果和之前的 Promise 是统一的,然而这个代码缩小了很多
当初改一下要求:
function step1(n) {console.log(`step1 with ${n}`);
return takeLongTime(n);
}
function step2(m, n) {console.log(`step2 with ${m} and ${n}`);
return takeLongTime(m + n);
}
function step3(k, m, n) {console.log(`step3 with ${k}, ${m} and ${n}`);
return takeLongTime(k + m + n);
}
Promise 实现:
function doIt() {console.time("doIt");
const time1 = 300;
step1(time1)
.then(time2 => {return step2(time1, time2)
.then(time3 => [time1, time2, time3]);
})
.then(times => {const [time1, time2, time3] = times;
return step3(time1, time2, time3);
})
.then(result => {console.log(`result is ${result}`);
console.timeEnd("doIt");
});
}
doIt();
async/await 实现:
async function doIt() {console.time("doIt");
const time1 = 300;
const time2 = await step1(time1);
const time3 = await step2(time1, time2);
const result = await step3(time1, time2, time3);
console.log(`result is ${result}`);
console.timeEnd("doIt");
}
doIt();
// c:vartest>node --harmony_async_await .
// step1 with 300
// step2 with 800 = 300 + 500
// step3 with 1800 = 300 + 500 + 1000
// result is 2000
// doIt: 2907.387ms
PS:因为在 Promise 中。咱们有时会被回绝拜访,这样 Async/Await 让 try/catch 能够同时解决同步和异步谬误。
具体对于 async/await 含意和用法能够参考:
http://www.ruanyifeng.com/blo…
正文完
发表至: javascript
2021-02-26