关于java:JZ015反转链表

33次阅读

共计 981 个字符，预计需要花费 3 分钟才能阅读完成。

输出一个链表，反转链表后，输入新链表的表头。

题目链接 : 反转链表

/**
 * 题目：反转链表
 * 题目形容
 * 输出一个链表，反转链表后，输入新链表的表头。* 题目链接：* https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca?tpId=13&&tqId=11168&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
 */
public class Jz15 {public ListNode reverseList(ListNode head) {if (head == null || head.next == null) {return head;}
        ListNode first = head, second = head.next;
        first.next = null;
        while (first != null && second != null) {
            ListNode temp = first;
            first = second;
            second = second.next;
            first.next = temp;
        }
        return first;
    }

    public static void main(String[] args) {ListNode head = new ListNode(1);
        head.next = new ListNode(2);
        head.next.next = new ListNode(3);
        System.out.println("before reverse");
        ListNode cur = head;
        while (cur != null) {System.out.print(cur.val + " ");
            cur = cur.next;
        }
        System.out.println();
        Jz15 jz15 = new Jz15();
        ListNode result = jz15.reverseList(head);
        System.out.println("after reverse");
        ListNode cur1 = result;
        while (cur1 != null) {System.out.print(cur1.val + " ");
            cur1 = cur1.next;
        }
    }
}